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heydayana Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits ( \Theta  \cos ( 1\Theta) d \Theta \]
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.0
1sin(1theta)/1+C =1 +sin(1theta)+c
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
use integral subs, let u=(1Θ)
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.0
oops its I did a mistake there
 one year ago

artix_17 Group TitleBest ResponseYou've already chosen the best response.0
it should be \[\theta ^{2}/2 + \sin(1\theta)+\]
 one year ago

heydayana Group TitleBest ResponseYou've already chosen the best response.0
if i use subs what do i do after i get du=1d\[\Theta \] ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
well, i want explain it step by step u = 1Θ > Θ=1u, right ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
next, u have got u = 1Θ du = dΘ or dΘ =  du, right ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
next, we substitute of them to the original problem : ∫(Θ−cos(1−Θ))dΘ = ∫[(1u)  cosu] (du) = ∫[(u1) + cosu] du, agree ???
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
ok, just integral all one by one, int u du= ... int 1du= .... int cosu du= .... what u get ????
 one year ago

heydayana Group TitleBest ResponseYou've already chosen the best response.0
1/2 u^2 u + sin u + c ?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
yes, correct now, the last step u must substitute back that u = 1Θ
 one year ago

heydayana Group TitleBest ResponseYou've already chosen the best response.0
i end up getting 1/2 1/2theta^2 + sin (1theta) is the 1/2 suppose to be there?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
from ur answer : 1/2 u^2 u + sin u + c , just change u=1Θ, gives 1/2(1Θ)^2 (1Θ) + sin(1Θ) + c i think enough be the answer, but if u want simplify it might too
 one year ago

heydayana Group TitleBest ResponseYou've already chosen the best response.0
whats the final answer if you simplify?
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.1
1/2(1Θ)^2 (1Θ) + sin(1Θ) + c = 1/2 (12Θ + Θ^2) 1 + Θ + sin(1Θ) + c = 1/2  Θ +1/2*Θ^2 1 + Θ + sin(1Θ) + c = 1/2 +1/2*Θ^2 + sin(1Θ) + c = 1/2 (1Θ^2) + sin(1Θ) + c
 one year ago
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