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sqrt3(sqrt6+sqrt3)+(sqrt8-5)

|dw:1354245450082:dw|

well from there i got 3+3sqrt2= 6sqrt2 + sqrt8-5

and the sqrt of 8 is 4 and sqrt of 4 is 2 so it will be 6sqrt2+sqrt2-5

whoah where did that come from

|dw:1354246002329:dw|

ohh i see i took the sqaure root of 8 wrong

can i ask ya'll another question??

yep.

|dw:1354246494891:dw|
Just add up the sides, for part one. Simplify the square roots a little.

sqrt of 128= 8sqrt 2?

That's right.

and the sqrt of 200 = 10sqrt 2???

yep.

what do I do from there?

do I add them together?

perimeter of a rectangle.

how do i do that?

You want to know how long the edge is...
|dw:1354247036064:dw|

so multiply 8sqrt2*8sqrt2 and 10sqrt2*10sqrt2? and then add them together?

are you still there?

am I still doing this right? hello?

Yeah to find the perimeter of a rectangle, you add the lengths of all sides together.

after you multiply?

Just take the lengths of the sides and add them together.

so 8sqrt2*8sqrt2=64sqrt2
10sqrt2*10sqrt2= 100sqrt 2
64sqrt2+100sqrt2= 164sqrt2?

am i right so far?

was I just suppose to add them all together or multiply? like i did above?

|dw:1354248044017:dw|

|dw:1354248083431:dw|

So the perimeter is \[\Large 36\sqrt{2}\]

oh so I was suppose to add them not multiply

oh ok that what i was thinking of

ok thats what i wrote so far what is the next step?

the funny equal sign is a approximate sign right?

so you just have to name an object that's roughly 14.1421356 ft by 11.31370848 ft

so it could be a pool right? for the object?

yeah or a large table/counter of some sort

sure go for it

awesome that way I know I really understand it

ok it's a bit different because they want the area this time

and not the perimeter

isn't area multiplying the sides together?

exactly

Area = Length times Width

ok so first i have to simplify the sqrts
6sqrt 6 = 6+3sqrt2?

9sqrt 2?

how are you getting 6sqrt 6 = 6+3sqrt2

you can't do that

6*sqrt(6) is as simple as it gets

i was trying to make it so both of my radicals have the same square root thing of sqrt2

notice that 6 has no factors that are perfect squares (ignore 1)

so sqrt(6) can't be simplified

oh..... i was wondering how that worked cause nothing times itself equals 6

Multiply the coefficients: 6*4 = 24
Multiply the radicands: 6*2 = 12

what is ur question, i mean what r u trying to find exactly?

so u multiply and then plugg it back in to the equation.

so 6*sqrt(6) times 4*sqrt(2) = 24*sqrt(12)
simplify 24*sqrt(12)

yes dont forget!! Simplify!

so I can go straight to part 2 right? and find the area?

yes.

sorry idk why that post just showed up i have a major delay

?

yes since you can't simplify the length/width just multiply them out

now is 24sqrt12 the radical area that needs to be converted into the approximate length?

simplify that
24*sqrt(12)
24*sqrt(4*3)
24*sqrt(4)*sqrt(3)
24*2*sqrt(3)
48*sqrt(3)

so the area is 48*sqrt(3) square inches

you just type 6*sqrt(6) and you get 14.6969 roughly

and 4sqqrt of 2 is approximately 5.65685424949238

correct

so the object could be like a table? o ra whiite board maybe?

yeah that's a reasonably sized whiteboard

i'm glad i did and hopefully it's all making sense now

youre WELCOME

no thanks