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Kathatesmath94Best ResponseYou've already chosen the best response.0
sqrt3(sqrt6+sqrt3)+(sqrt85)
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
dw:1354245450082:dw
 one year ago

LimeBest ResponseYou've already chosen the best response.0
I believe it is much easier to use a calculator for Square root, but let's break it down. \[3 + 3 \sqrt2 +(\sqrt 8  5)\]
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
well from there i got 3+3sqrt2= 6sqrt2 + sqrt85
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
and the sqrt of 8 is 4 and sqrt of 4 is 2 so it will be 6sqrt2+sqrt25
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
whoah where did that come from
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
dw:1354246002329:dw
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
ohh i see i took the sqaure root of 8 wrong
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
can i ask ya'll another question??
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
Part 1: Find the perimeter of a rectangular object which has a length of sqrt 128 feet and a width of sqrt 200 feet. Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? i am not going to lie I don't even know where to start....
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
dw:1354246494891:dw Just add up the sides, for part one. Simplify the square roots a little.
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
sqrt of 128= 8sqrt 2?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
and the sqrt of 200 = 10sqrt 2???
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
what do I do from there?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
do I add them together?
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
perimeter of a rectangle.
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
how do i do that?
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
You want to know how long the edge is... dw:1354247036064:dw
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
so multiply 8sqrt2*8sqrt2 and 10sqrt2*10sqrt2? and then add them together?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
are you still there?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
am I still doing this right? hello?
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
Yeah to find the perimeter of a rectangle, you add the lengths of all sides together.
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
after you multiply?
 one year ago

scarydoorBest ResponseYou've already chosen the best response.1
Just take the lengths of the sides and add them together.
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
so 8sqrt2*8sqrt2=64sqrt2 10sqrt2*10sqrt2= 100sqrt 2 64sqrt2+100sqrt2= 164sqrt2?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
am i right so far?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
was I just suppose to add them all together or multiply? like i did above?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
dw:1354248044017:dw
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
dw:1354248083431:dw
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
dw:1354248126981:dw Perimeter = Sum of all sides P = s1 + s2 + s3 + s4 P = 8*sqrt(2) + 10*sqrt(2) + 8*sqrt(2) + 10*sqrt(2) P = 36*sqrt(2)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
So the perimeter is \[\Large 36\sqrt{2}\]
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
oh so I was suppose to add them not multiply
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
yes, or you can add the length and width and multiply by 2 this is because P = L + W + L + W P = 2L + 2W P = 2*(L + W)
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
oh ok that what i was thinking of
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form you essentially simplify both sqrt(128) and sqrt(200) to get 8*sqrt(2) and 10*sqrt(2) you can either add up the four sides or you can add up the length and width and multiply by 2 either way, you get the answer of \[\Large 36\sqrt{2}\]
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
ok thats what i wrote so far what is the next step?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
What type of object in your home or school might this be? \[\Large 36\sqrt{2} \approx 36(1.41421356)\] \[\Large 36\sqrt{2} \approx 50.91168816\] so the perimeter is roughly 50.91168816 feet
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[\Large 8\sqrt{2} \approx 8(1.41421356)\] \[\Large 8\sqrt{2} \approx 11.31370848\] the width is roughly 11.31370848 feet
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
the funny equal sign is a approximate sign right?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[\Large 10\sqrt{2} \approx 10(1.41421356)\] \[\Large 10\sqrt{2} \approx 14.1421356\] the length is roughly 14.1421356 feet
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so you just have to name an object that's roughly 14.1421356 ft by 11.31370848 ft
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
so it could be a pool right? for the object?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
yeah or a large table/counter of some sort
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
ohhh wow that wasnt too bad there is another one very similiar and if I post all my work will you tell me if I am right or not?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
sure go for it
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
awesome that way I know I really understand it
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
Part 1: Find the area of a rectangular object which has a length of 4sqrt2 inches and a width of 6sqrt6 inches. Part 2: Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? dw:1354248883689:dw
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
ok it's a bit different because they want the area this time
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
and not the perimeter
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
isn't area multiplying the sides together?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Area = Length times Width
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
ok so first i have to simplify the sqrts 6sqrt 6 = 6+3sqrt2?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
how are you getting 6sqrt 6 = 6+3sqrt2
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
uhhh i might of factored wrong because i took the factors 2 and 3 and pulled the 3 out to add to the 6 and left the 2 inside the radical
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you can't do that
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
6*sqrt(6) is as simple as it gets
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
i was trying to make it so both of my radicals have the same square root thing of sqrt2
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
notice that 6 has no factors that are perfect squares (ignore 1)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so sqrt(6) can't be simplified
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
oh..... i was wondering how that worked cause nothing times itself equals 6
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Multiply the coefficients: 6*4 = 24 Multiply the radicands: 6*2 = 12
 one year ago

AmmarahBest ResponseYou've already chosen the best response.0
what is ur question, i mean what r u trying to find exactly?
 one year ago

AmmarahBest ResponseYou've already chosen the best response.0
so u multiply and then plugg it back in to the equation.
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so 6*sqrt(6) times 4*sqrt(2) = 24*sqrt(12) simplify 24*sqrt(12)
 one year ago

AmmarahBest ResponseYou've already chosen the best response.0
yes dont forget!! Simplify!
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
so I can go straight to part 2 right? and find the area?
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
sorry idk why that post just showed up i have a major delay
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
yes since you can't simplify the length/width just multiply them out
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
now is 24sqrt12 the radical area that needs to be converted into the approximate length?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
simplify that 24*sqrt(12) 24*sqrt(4*3) 24*sqrt(4)*sqrt(3) 24*2*sqrt(3) 48*sqrt(3)
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
and do you get the approximate length by putting the number in the calculator? i meant to ask you how you did that last time
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so the area is 48*sqrt(3) square inches
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you just type 6*sqrt(6) and you get 14.6969 roughly
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
and 4sqqrt of 2 is approximately 5.65685424949238
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
so the object could be like a table? o ra whiite board maybe?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
yeah that's a reasonably sized whiteboard
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
you have helped me so much and thank you for helping me with this someone was helping me but they left and I didnt know where to go from there you are definitley a life SAVER!
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
i'm glad i did and hopefully it's all making sense now
 one year ago

Kathatesmath94Best ResponseYou've already chosen the best response.0
yeah they were a little different but there steps were very similar and I took notes while we talked so hopefully that will help me if I have a problem like this later on in the course
 one year ago
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