Kathatesmath94
can someone check my work??
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Kathatesmath94
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sqrt3(sqrt6+sqrt3)+(sqrt8-5)
Kathatesmath94
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Lime
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I believe it is much easier to use a calculator for Square root, but let's break it down.
\[3 + 3 \sqrt2 +(\sqrt 8 - 5)\]
Kathatesmath94
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well from there i got 3+3sqrt2= 6sqrt2 + sqrt8-5
Kathatesmath94
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and the sqrt of 8 is 4 and sqrt of 4 is 2 so it will be 6sqrt2+sqrt2-5
Kathatesmath94
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whoah where did that come from
scarydoor
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|dw:1354246002329:dw|
Kathatesmath94
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ohh i see i took the sqaure root of 8 wrong
Kathatesmath94
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can i ask ya'll another question??
scarydoor
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yep.
Kathatesmath94
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Part 1: Find the perimeter of a rectangular object which has a length of sqrt 128 feet and a width of sqrt 200 feet.
Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form.
Part 3: What type of object in your home or school might this be?
i am not going to lie I don't even know where to start....
scarydoor
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Just add up the sides, for part one. Simplify the square roots a little.
Kathatesmath94
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sqrt of 128= 8sqrt 2?
scarydoor
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That's right.
Kathatesmath94
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and the sqrt of 200 = 10sqrt 2???
scarydoor
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yep.
Kathatesmath94
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what do I do from there?
Kathatesmath94
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do I add them together?
scarydoor
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perimeter of a rectangle.
Kathatesmath94
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how do i do that?
scarydoor
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You want to know how long the edge is...
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Kathatesmath94
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so multiply 8sqrt2*8sqrt2 and 10sqrt2*10sqrt2? and then add them together?
Kathatesmath94
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are you still there?
Kathatesmath94
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am I still doing this right? hello?
scarydoor
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Yeah to find the perimeter of a rectangle, you add the lengths of all sides together.
Kathatesmath94
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after you multiply?
scarydoor
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Just take the lengths of the sides and add them together.
Kathatesmath94
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so 8sqrt2*8sqrt2=64sqrt2
10sqrt2*10sqrt2= 100sqrt 2
64sqrt2+100sqrt2= 164sqrt2?
Kathatesmath94
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am i right so far?
Kathatesmath94
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was I just suppose to add them all together or multiply? like i did above?
jim_thompson5910
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jim_thompson5910
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jim_thompson5910
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Perimeter = Sum of all sides
P = s1 + s2 + s3 + s4
P = 8*sqrt(2) + 10*sqrt(2) + 8*sqrt(2) + 10*sqrt(2)
P = 36*sqrt(2)
jim_thompson5910
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So the perimeter is \[\Large 36\sqrt{2}\]
Kathatesmath94
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oh so I was suppose to add them not multiply
jim_thompson5910
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yes, or you can add the length and width and multiply by 2
this is because
P = L + W + L + W
P = 2L + 2W
P = 2*(L + W)
Kathatesmath94
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oh ok that what i was thinking of
jim_thompson5910
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Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form
you essentially simplify both sqrt(128) and sqrt(200) to get 8*sqrt(2) and 10*sqrt(2)
you can either add up the four sides
or
you can add up the length and width and multiply by 2
either way, you get the answer of \[\Large 36\sqrt{2}\]
Kathatesmath94
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ok thats what i wrote so far what is the next step?
jim_thompson5910
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What type of object in your home or school might this be?
\[\Large 36\sqrt{2} \approx 36(1.41421356)\]
\[\Large 36\sqrt{2} \approx 50.91168816\]
so the perimeter is roughly 50.91168816 feet
jim_thompson5910
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\[\Large 8\sqrt{2} \approx 8(1.41421356)\]
\[\Large 8\sqrt{2} \approx 11.31370848\]
the width is roughly 11.31370848 feet
Kathatesmath94
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the funny equal sign is a approximate sign right?
jim_thompson5910
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\[\Large 10\sqrt{2} \approx 10(1.41421356)\]
\[\Large 10\sqrt{2} \approx 14.1421356\]
the length is roughly 14.1421356 feet
jim_thompson5910
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so you just have to name an object that's roughly 14.1421356 ft by 11.31370848 ft
Kathatesmath94
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so it could be a pool right? for the object?
jim_thompson5910
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yeah or a large table/counter of some sort
Kathatesmath94
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ohhh wow that wasnt too bad there is another one very similiar and if I post all my work will you tell me if I am right or not?
jim_thompson5910
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sure go for it
Kathatesmath94
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awesome that way I know I really understand it
Kathatesmath94
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Part 1: Find the area of a rectangular object which has a length of 4sqrt2 inches and a width of 6sqrt6 inches.
Part 2: Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form.
Part 3: What type of object in your home or school might this be?
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jim_thompson5910
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ok it's a bit different because they want the area this time
jim_thompson5910
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and not the perimeter
Kathatesmath94
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isn't area multiplying the sides together?
jim_thompson5910
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exactly
jim_thompson5910
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Area = Length times Width
Kathatesmath94
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ok so first i have to simplify the sqrts
6sqrt 6 = 6+3sqrt2?
Kathatesmath94
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9sqrt 2?
jim_thompson5910
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how are you getting 6sqrt 6 = 6+3sqrt2
Kathatesmath94
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uhhh i might of factored wrong
because i took the factors 2 and 3 and pulled the 3 out to add to the 6 and left the 2 inside the radical
jim_thompson5910
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you can't do that
jim_thompson5910
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6*sqrt(6) is as simple as it gets
Kathatesmath94
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i was trying to make it so both of my radicals have the same square root thing of sqrt2
jim_thompson5910
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notice that 6 has no factors that are perfect squares (ignore 1)
jim_thompson5910
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so sqrt(6) can't be simplified
Kathatesmath94
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oh..... i was wondering how that worked cause nothing times itself equals 6
jim_thompson5910
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Multiply the coefficients: 6*4 = 24
Multiply the radicands: 6*2 = 12
Ammarah
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what is ur question, i mean what r u trying to find exactly?
Ammarah
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so u multiply and then plugg it back in to the equation.
jim_thompson5910
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so 6*sqrt(6) times 4*sqrt(2) = 24*sqrt(12)
simplify 24*sqrt(12)
Ammarah
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yes dont forget!! Simplify!
Kathatesmath94
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so I can go straight to part 2 right? and find the area?
Ammarah
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yes.
Kathatesmath94
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sorry idk why that post just showed up i have a major delay
Ammarah
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?
jim_thompson5910
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yes since you can't simplify the length/width just multiply them out
Kathatesmath94
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now is 24sqrt12 the radical area that needs to be converted into the approximate length?
jim_thompson5910
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simplify that
24*sqrt(12)
24*sqrt(4*3)
24*sqrt(4)*sqrt(3)
24*2*sqrt(3)
48*sqrt(3)
Kathatesmath94
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and do you get the approximate length by putting the number in the calculator? i meant to ask you how you did that last time
jim_thompson5910
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so the area is 48*sqrt(3) square inches
jim_thompson5910
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you just type 6*sqrt(6) and you get 14.6969 roughly
Kathatesmath94
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and 4sqqrt of 2 is approximately 5.65685424949238
jim_thompson5910
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correct
Kathatesmath94
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so the object could be like a table? o ra whiite board maybe?
jim_thompson5910
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yeah that's a reasonably sized whiteboard
Kathatesmath94
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you have helped me so much and thank you for helping me with this someone was helping me but they left and I didnt know where to go from there you are definitley a life SAVER!
jim_thompson5910
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i'm glad i did and hopefully it's all making sense now
Kathatesmath94
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yeah they were a little different but there steps were very similar and I took notes while we talked so hopefully that will help me if I have a problem like this later on in the course
danielcvalencia
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youre WELCOME
Ammarah
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no thanks