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Kathatesmath94
 3 years ago
can someone check my work??
Kathatesmath94
 3 years ago
can someone check my work??

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Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0sqrt3(sqrt6+sqrt3)+(sqrt85)

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354245450082:dw

Lime
 3 years ago
Best ResponseYou've already chosen the best response.0I believe it is much easier to use a calculator for Square root, but let's break it down. \[3 + 3 \sqrt2 +(\sqrt 8  5)\]

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0well from there i got 3+3sqrt2= 6sqrt2 + sqrt85

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0and the sqrt of 8 is 4 and sqrt of 4 is 2 so it will be 6sqrt2+sqrt25

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0whoah where did that come from

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354246002329:dw

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0ohh i see i took the sqaure root of 8 wrong

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0can i ask ya'll another question??

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0Part 1: Find the perimeter of a rectangular object which has a length of sqrt 128 feet and a width of sqrt 200 feet. Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? i am not going to lie I don't even know where to start....

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354246494891:dw Just add up the sides, for part one. Simplify the square roots a little.

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0sqrt of 128= 8sqrt 2?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0and the sqrt of 200 = 10sqrt 2???

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0what do I do from there?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0do I add them together?

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1perimeter of a rectangle.

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0how do i do that?

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1You want to know how long the edge is... dw:1354247036064:dw

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0so multiply 8sqrt2*8sqrt2 and 10sqrt2*10sqrt2? and then add them together?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0are you still there?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0am I still doing this right? hello?

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah to find the perimeter of a rectangle, you add the lengths of all sides together.

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0after you multiply?

scarydoor
 3 years ago
Best ResponseYou've already chosen the best response.1Just take the lengths of the sides and add them together.

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0so 8sqrt2*8sqrt2=64sqrt2 10sqrt2*10sqrt2= 100sqrt 2 64sqrt2+100sqrt2= 164sqrt2?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0am i right so far?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0was I just suppose to add them all together or multiply? like i did above?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354248044017:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354248083431:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1354248126981:dw Perimeter = Sum of all sides P = s1 + s2 + s3 + s4 P = 8*sqrt(2) + 10*sqrt(2) + 8*sqrt(2) + 10*sqrt(2) P = 36*sqrt(2)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1So the perimeter is \[\Large 36\sqrt{2}\]

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0oh so I was suppose to add them not multiply

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yes, or you can add the length and width and multiply by 2 this is because P = L + W + L + W P = 2L + 2W P = 2*(L + W)

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok that what i was thinking of

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form you essentially simplify both sqrt(128) and sqrt(200) to get 8*sqrt(2) and 10*sqrt(2) you can either add up the four sides or you can add up the length and width and multiply by 2 either way, you get the answer of \[\Large 36\sqrt{2}\]

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0ok thats what i wrote so far what is the next step?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1What type of object in your home or school might this be? \[\Large 36\sqrt{2} \approx 36(1.41421356)\] \[\Large 36\sqrt{2} \approx 50.91168816\] so the perimeter is roughly 50.91168816 feet

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large 8\sqrt{2} \approx 8(1.41421356)\] \[\Large 8\sqrt{2} \approx 11.31370848\] the width is roughly 11.31370848 feet

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0the funny equal sign is a approximate sign right?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large 10\sqrt{2} \approx 10(1.41421356)\] \[\Large 10\sqrt{2} \approx 14.1421356\] the length is roughly 14.1421356 feet

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1so you just have to name an object that's roughly 14.1421356 ft by 11.31370848 ft

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0so it could be a pool right? for the object?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yeah or a large table/counter of some sort

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0ohhh wow that wasnt too bad there is another one very similiar and if I post all my work will you tell me if I am right or not?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1sure go for it

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0awesome that way I know I really understand it

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0Part 1: Find the area of a rectangular object which has a length of 4sqrt2 inches and a width of 6sqrt6 inches. Part 2: Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? dw:1354248883689:dw

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1ok it's a bit different because they want the area this time

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1and not the perimeter

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0isn't area multiplying the sides together?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1Area = Length times Width

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0ok so first i have to simplify the sqrts 6sqrt 6 = 6+3sqrt2?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1how are you getting 6sqrt 6 = 6+3sqrt2

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0uhhh i might of factored wrong because i took the factors 2 and 3 and pulled the 3 out to add to the 6 and left the 2 inside the radical

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you can't do that

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.16*sqrt(6) is as simple as it gets

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0i was trying to make it so both of my radicals have the same square root thing of sqrt2

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1notice that 6 has no factors that are perfect squares (ignore 1)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1so sqrt(6) can't be simplified

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0oh..... i was wondering how that worked cause nothing times itself equals 6

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1Multiply the coefficients: 6*4 = 24 Multiply the radicands: 6*2 = 12

Ammarah
 3 years ago
Best ResponseYou've already chosen the best response.0what is ur question, i mean what r u trying to find exactly?

Ammarah
 3 years ago
Best ResponseYou've already chosen the best response.0so u multiply and then plugg it back in to the equation.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1so 6*sqrt(6) times 4*sqrt(2) = 24*sqrt(12) simplify 24*sqrt(12)

Ammarah
 3 years ago
Best ResponseYou've already chosen the best response.0yes dont forget!! Simplify!

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0so I can go straight to part 2 right? and find the area?

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0sorry idk why that post just showed up i have a major delay

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yes since you can't simplify the length/width just multiply them out

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0now is 24sqrt12 the radical area that needs to be converted into the approximate length?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1simplify that 24*sqrt(12) 24*sqrt(4*3) 24*sqrt(4)*sqrt(3) 24*2*sqrt(3) 48*sqrt(3)

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0and do you get the approximate length by putting the number in the calculator? i meant to ask you how you did that last time

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1so the area is 48*sqrt(3) square inches

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you just type 6*sqrt(6) and you get 14.6969 roughly

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0and 4sqqrt of 2 is approximately 5.65685424949238

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0so the object could be like a table? o ra whiite board maybe?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1yeah that's a reasonably sized whiteboard

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0you have helped me so much and thank you for helping me with this someone was helping me but they left and I didnt know where to go from there you are definitley a life SAVER!

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1i'm glad i did and hopefully it's all making sense now

Kathatesmath94
 3 years ago
Best ResponseYou've already chosen the best response.0yeah they were a little different but there steps were very similar and I took notes while we talked so hopefully that will help me if I have a problem like this later on in the course
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