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can someone check my work??

Mathematics
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sqrt3(sqrt6+sqrt3)+(sqrt8-5)
|dw:1354245450082:dw|
I believe it is much easier to use a calculator for Square root, but let's break it down. \[3 + 3 \sqrt2 +(\sqrt 8 - 5)\]

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well from there i got 3+3sqrt2= 6sqrt2 + sqrt8-5
and the sqrt of 8 is 4 and sqrt of 4 is 2 so it will be 6sqrt2+sqrt2-5
whoah where did that come from
|dw:1354246002329:dw|
ohh i see i took the sqaure root of 8 wrong
can i ask ya'll another question??
yep.
Part 1: Find the perimeter of a rectangular object which has a length of sqrt 128 feet and a width of sqrt 200 feet. Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? i am not going to lie I don't even know where to start....
|dw:1354246494891:dw| Just add up the sides, for part one. Simplify the square roots a little.
sqrt of 128= 8sqrt 2?
That's right.
and the sqrt of 200 = 10sqrt 2???
yep.
what do I do from there?
do I add them together?
perimeter of a rectangle.
how do i do that?
You want to know how long the edge is... |dw:1354247036064:dw|
so multiply 8sqrt2*8sqrt2 and 10sqrt2*10sqrt2? and then add them together?
are you still there?
am I still doing this right? hello?
Yeah to find the perimeter of a rectangle, you add the lengths of all sides together.
after you multiply?
Just take the lengths of the sides and add them together.
so 8sqrt2*8sqrt2=64sqrt2 10sqrt2*10sqrt2= 100sqrt 2 64sqrt2+100sqrt2= 164sqrt2?
am i right so far?
was I just suppose to add them all together or multiply? like i did above?
|dw:1354248044017:dw|
|dw:1354248083431:dw|
|dw:1354248126981:dw| Perimeter = Sum of all sides P = s1 + s2 + s3 + s4 P = 8*sqrt(2) + 10*sqrt(2) + 8*sqrt(2) + 10*sqrt(2) P = 36*sqrt(2)
So the perimeter is \[\Large 36\sqrt{2}\]
oh so I was suppose to add them not multiply
yes, or you can add the length and width and multiply by 2 this is because P = L + W + L + W P = 2L + 2W P = 2*(L + W)
oh ok that what i was thinking of
Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form you essentially simplify both sqrt(128) and sqrt(200) to get 8*sqrt(2) and 10*sqrt(2) you can either add up the four sides or you can add up the length and width and multiply by 2 either way, you get the answer of \[\Large 36\sqrt{2}\]
ok thats what i wrote so far what is the next step?
What type of object in your home or school might this be? \[\Large 36\sqrt{2} \approx 36(1.41421356)\] \[\Large 36\sqrt{2} \approx 50.91168816\] so the perimeter is roughly 50.91168816 feet
\[\Large 8\sqrt{2} \approx 8(1.41421356)\] \[\Large 8\sqrt{2} \approx 11.31370848\] the width is roughly 11.31370848 feet
the funny equal sign is a approximate sign right?
\[\Large 10\sqrt{2} \approx 10(1.41421356)\] \[\Large 10\sqrt{2} \approx 14.1421356\] the length is roughly 14.1421356 feet
so you just have to name an object that's roughly 14.1421356 ft by 11.31370848 ft
so it could be a pool right? for the object?
yeah or a large table/counter of some sort
ohhh wow that wasnt too bad there is another one very similiar and if I post all my work will you tell me if I am right or not?
sure go for it
awesome that way I know I really understand it
Part 1: Find the area of a rectangular object which has a length of 4sqrt2 inches and a width of 6sqrt6 inches. Part 2: Explain, in complete sentences, how you arrived at the simplified answer and give the final solution in simplified radical form. Part 3: What type of object in your home or school might this be? |dw:1354248883689:dw|
ok it's a bit different because they want the area this time
and not the perimeter
isn't area multiplying the sides together?
exactly
Area = Length times Width
ok so first i have to simplify the sqrts 6sqrt 6 = 6+3sqrt2?
9sqrt 2?
how are you getting 6sqrt 6 = 6+3sqrt2
uhhh i might of factored wrong because i took the factors 2 and 3 and pulled the 3 out to add to the 6 and left the 2 inside the radical
you can't do that
6*sqrt(6) is as simple as it gets
i was trying to make it so both of my radicals have the same square root thing of sqrt2
notice that 6 has no factors that are perfect squares (ignore 1)
so sqrt(6) can't be simplified
oh..... i was wondering how that worked cause nothing times itself equals 6
Multiply the coefficients: 6*4 = 24 Multiply the radicands: 6*2 = 12
what is ur question, i mean what r u trying to find exactly?
so u multiply and then plugg it back in to the equation.
so 6*sqrt(6) times 4*sqrt(2) = 24*sqrt(12) simplify 24*sqrt(12)
yes dont forget!! Simplify!
so I can go straight to part 2 right? and find the area?
yes.
sorry idk why that post just showed up i have a major delay
?
yes since you can't simplify the length/width just multiply them out
now is 24sqrt12 the radical area that needs to be converted into the approximate length?
simplify that 24*sqrt(12) 24*sqrt(4*3) 24*sqrt(4)*sqrt(3) 24*2*sqrt(3) 48*sqrt(3)
and do you get the approximate length by putting the number in the calculator? i meant to ask you how you did that last time
so the area is 48*sqrt(3) square inches
you just type 6*sqrt(6) and you get 14.6969 roughly
and 4sqqrt of 2 is approximately 5.65685424949238
correct
so the object could be like a table? o ra whiite board maybe?
yeah that's a reasonably sized whiteboard
you have helped me so much and thank you for helping me with this someone was helping me but they left and I didnt know where to go from there you are definitley a life SAVER!
i'm glad i did and hopefully it's all making sense now
yeah they were a little different but there steps were very similar and I took notes while we talked so hopefully that will help me if I have a problem like this later on in the course
youre WELCOME
no thanks

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