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agusginanjar
Group Title
a +b = c
a x b = c
what the value of a, b, and c with value of a &b not 2 & 0
 one year ago
 one year ago
agusginanjar Group Title
a +b = c a x b = c what the value of a, b, and c with value of a &b not 2 & 0
 one year ago
 one year ago

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joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
If you knew what c was, then solving the system\[a+b=c\]\[ab=c\]Is the same as solving the quadratic equation:\[x^2cx+c=0\]where the solutions to the quadratic are a and b. Using the quadratic formula yields:\[x=\frac{c\pm \sqrt{c^24c}}{2}\] Now we probably want these solutions to be real, so we need to make sure:\[c^24c\ge 0\]If c is positive, and not 0, then we divide by c to get:\[c4\ge 0\Longrightarrow c\ge 4\] So pick any number for c such that c is greater than 4. Say 10. Then:\[a=\frac{10+\sqrt{60}}{2}\]\[b=\frac{10\sqrt{60}}{2}\]does the job.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
Note there is not one answer to this question. You can pick infinitely many values of c, which will produce a and b accordingly.
 one year ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
whoops typo, should be:\[a=\frac{10+\sqrt{60}}{2}\]\[b=\frac{10\sqrt{60}}{2}\]
 one year ago

RadEn Group TitleBest ResponseYou've already chosen the best response.0
ab = a+b ab  a = b a(b1) = b a = b/(b1), with b not 1 just plug b E real but not for b=0,1,and 2 u will get values a and get order pairs : (a1,b1),(a2,b2),.... so, infinitely solutions
 one year ago
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