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agusginanjar
 2 years ago
a +b = c
a x b = c
what the value of a, b, and c with value of a &b not 2 & 0
agusginanjar
 2 years ago
a +b = c a x b = c what the value of a, b, and c with value of a &b not 2 & 0

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joemath314159
 2 years ago
Best ResponseYou've already chosen the best response.1If you knew what c was, then solving the system\[a+b=c\]\[ab=c\]Is the same as solving the quadratic equation:\[x^2cx+c=0\]where the solutions to the quadratic are a and b. Using the quadratic formula yields:\[x=\frac{c\pm \sqrt{c^24c}}{2}\] Now we probably want these solutions to be real, so we need to make sure:\[c^24c\ge 0\]If c is positive, and not 0, then we divide by c to get:\[c4\ge 0\Longrightarrow c\ge 4\] So pick any number for c such that c is greater than 4. Say 10. Then:\[a=\frac{10+\sqrt{60}}{2}\]\[b=\frac{10\sqrt{60}}{2}\]does the job.

joemath314159
 2 years ago
Best ResponseYou've already chosen the best response.1Note there is not one answer to this question. You can pick infinitely many values of c, which will produce a and b accordingly.

joemath314159
 2 years ago
Best ResponseYou've already chosen the best response.1whoops typo, should be:\[a=\frac{10+\sqrt{60}}{2}\]\[b=\frac{10\sqrt{60}}{2}\]

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.0ab = a+b ab  a = b a(b1) = b a = b/(b1), with b not 1 just plug b E real but not for b=0,1,and 2 u will get values a and get order pairs : (a1,b1),(a2,b2),.... so, infinitely solutions
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