anonymous 4 years ago a +b = c a x b = c what the value of a, b, and c with value of a &b not 2 & 0

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1. anonymous

If you knew what c was, then solving the system$a+b=c$$ab=c$Is the same as solving the quadratic equation:$x^2-cx+c=0$where the solutions to the quadratic are a and b. Using the quadratic formula yields:$x=\frac{-c\pm \sqrt{c^2-4c}}{2}$ Now we probably want these solutions to be real, so we need to make sure:$c^2-4c\ge 0$If c is positive, and not 0, then we divide by c to get:$c-4\ge 0\Longrightarrow c\ge 4$ So pick any number for c such that c is greater than 4. Say 10. Then:$a=\frac{-10+\sqrt{60}}{2}$$b=\frac{-10-\sqrt{60}}{2}$does the job.

2. anonymous

Note there is not one answer to this question. You can pick infinitely many values of c, which will produce a and b accordingly.

3. anonymous

whoops typo, should be:$a=\frac{10+\sqrt{60}}{2}$$b=\frac{10-\sqrt{60}}{2}$

ab = a+b ab - a = b a(b-1) = b a = b/(b-1), with b not 1 just plug b E real but not for b=0,1,and 2 u will get values a and get order pairs : (a1,b1),(a2,b2),.... so, infinitely solutions

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