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Well the first one is already in slope-intercept form
For the second one, you would try to get y by itself. So you would add -2x to the right and divide it all by 3 |dw:1354248752347:dw|
Do you understand so far?
Wait I just looked at the first one again and it doesn't have an x.
oops i wrote it wron its y=-2/3x-2
Oh ok. It's still in slope-intercept form.
is that like y=(m)x+b?
Yea, that's slope-intercept form. Do you know how to graph the equations?
not exactly :/
So in y=mx+b, m is the slope and b is the y-intercept.
alright so how would i set that on a graph cause i've always confused which side to place it on .
Slope is rise over run. For example, in the first equation, the slope is -2/3. That means you would start at 0, move up 2, and LEFT 3 since its negative. If it was positive, you would move to the right. |dw:1354249157361:dw|
Do you understand it?
Well I've gotta go but if you need any more help, Google is always your friend.
thank you so much