anonymous
  • anonymous
sin²θ×secθ×cscθ=tanθ So far I have 1-cos²θ/1 × 1/cosθ × 1/sinθ = 1-cos²θ/cosθ×sinθ = 1-cosθ/sinθ But I don't know how to get rid of the 1 and then invert that from cot to tan.
Trigonometry
schrodinger
  • schrodinger
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nubeer
  • nubeer
|dw:1354252829403:dw| do you get this?
anonymous
  • anonymous
I changed the sin²θ to 1-cos²θ. I'm guessing that's my problem?
anonymous
  • anonymous
I have in my question what I've worked on so far

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nubeer
  • nubeer
yes .. don't change. it just leave it like that so u can cancel sin in numerator by the one in denominator.
anonymous
  • anonymous
wow. that's much easier than I was trying to make it. Thank you
nubeer
  • nubeer
yes .. you are welcome :)
anonymous
  • anonymous
|dw:1354253120973:dw|
anonymous
  • anonymous
I'll be asking for help on a few other questions like this soon. These are really confusing...
nubeer
  • nubeer
sure.

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