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nbedwards934

sin²θ×secθ×cscθ=tanθ So far I have 1-cos²θ/1 × 1/cosθ × 1/sinθ = 1-cos²θ/cosθ×sinθ = 1-cosθ/sinθ But I don't know how to get rid of the 1 and then invert that from cot to tan.

  • one year ago
  • one year ago

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  1. nubeer
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    |dw:1354252829403:dw| do you get this?

    • one year ago
  2. nbedwards934
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    I changed the sin²θ to 1-cos²θ. I'm guessing that's my problem?

    • one year ago
  3. nbedwards934
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    I have in my question what I've worked on so far

    • one year ago
  4. nubeer
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    yes .. don't change. it just leave it like that so u can cancel sin in numerator by the one in denominator.

    • one year ago
  5. nbedwards934
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    wow. that's much easier than I was trying to make it. Thank you

    • one year ago
  6. nubeer
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    yes .. you are welcome :)

    • one year ago
  7. jidery
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    |dw:1354253120973:dw|

    • one year ago
  8. nbedwards934
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    I'll be asking for help on a few other questions like this soon. These are really confusing...

    • one year ago
  9. nubeer
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    sure.

    • one year ago
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