Here's the question you clicked on:
nbedwards934
sin²θ×secθ×cscθ=tanθ So far I have 1-cos²θ/1 × 1/cosθ × 1/sinθ = 1-cos²θ/cosθ×sinθ = 1-cosθ/sinθ But I don't know how to get rid of the 1 and then invert that from cot to tan.
|dw:1354252829403:dw| do you get this?
I changed the sin²θ to 1-cos²θ. I'm guessing that's my problem?
I have in my question what I've worked on so far
yes .. don't change. it just leave it like that so u can cancel sin in numerator by the one in denominator.
wow. that's much easier than I was trying to make it. Thank you
yes .. you are welcome :)
I'll be asking for help on a few other questions like this soon. These are really confusing...