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nbedwards934

  • 3 years ago

sin²θ×secθ×cscθ=tanθ So far I have 1-cos²θ/1 × 1/cosθ × 1/sinθ = 1-cos²θ/cosθ×sinθ = 1-cosθ/sinθ But I don't know how to get rid of the 1 and then invert that from cot to tan.

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  1. nubeer
    • 3 years ago
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    |dw:1354252829403:dw| do you get this?

  2. nbedwards934
    • 3 years ago
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    I changed the sin²θ to 1-cos²θ. I'm guessing that's my problem?

  3. nbedwards934
    • 3 years ago
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    I have in my question what I've worked on so far

  4. nubeer
    • 3 years ago
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    yes .. don't change. it just leave it like that so u can cancel sin in numerator by the one in denominator.

  5. nbedwards934
    • 3 years ago
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    wow. that's much easier than I was trying to make it. Thank you

  6. nubeer
    • 3 years ago
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    yes .. you are welcome :)

  7. jidery
    • 3 years ago
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    |dw:1354253120973:dw|

  8. nbedwards934
    • 3 years ago
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    I'll be asking for help on a few other questions like this soon. These are really confusing...

  9. nubeer
    • 3 years ago
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    sure.

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