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Well, the one with the further distance would be in the air longer, correct?

Ok, wait, is this [delta y = V initial y *t + (1/2) gt^2]?

yeah, i know the trig functions.

So 30 = sin(V), then solve for V?

no, wait!

I mean sin(30)=V_y/V.

That's correct! Very good! :)

Approximately -36.261 m.

That's what it was--my calculator is set in radians from the calc test I took today :P

Ok! Much better: 18.35 m/s. I was a bit confused when sin(30) wasn't a nice, even number.

That is correct.
Now you just gotta go back and plug everything in ;)

Ok, I got 169.750 m.

Ok, is the value of g that's being used here -9.81?

Alright, what I got was 62.126.

Ok, maybe this time: 16.779

...I take it it's wrong :P

Got it (: Well, thanks again, and good-bye!