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Please find the derivative c:

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  • DLS

Please find the derivative c:

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[y=(3x^2+6x+5)^{(7/2)} \]
use the chain rule ley u = 3x^2 + 6x + 5 , then y = u^(7/2) find du/dx and dy/du then dy/dx = dy/du * du/dx
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I did the same.

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Other answers:

ok - and what did you get?
7/2(3x^2 + 6x + 5)^(5/2) * (6x +6)
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Im little confused.. Will it be like this? \[y=\frac{(3x^{2}+6x+5)^{7/2}}{d(6x+5)} \times \frac{d(6x+5)}{d5} \] something like this? perhaps confused..
y = u^(7/2) dy/du = (7/2) u^(7/2 - 1) = (7/2) u^(5/2) substituting back for u dy/du = (7/2) ( 3x^2 + 6x + 5)^(5/2) du/dx = 6x + 6 now multiply the two results together gives (7/2)(6x+6)(3x^2 + 6x + 5)^(5/2)
with practice you won't need to do the substitution u
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how did u get 6x+6
6x + 6 is the derivative of 3x^2 + 6x + 5 the du/dx in the above post
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thanks!
you use chain rule when you have a 'function of a function' like this one 3x^2 +6x + 5 is the 'inside' function of (3x^2 +6x + 5)^7/2
yw
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i have some more questions im confused with!
i'm sorry but i must go now
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okay..

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