DLS Group Title A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is one year ago one year ago

1. mayankdevnani Group Title

2. DLS Group Title

how

3. DLS Group Title

yes

4. mayankdevnani Group Title

first, find acceleration of body is what is the formula of acceleration of a body???

5. DLS Group Title

a=v-u/t

6. DLS Group Title

arent v & u both4?

7. mayankdevnani Group Title

no?

8. mayankdevnani Group Title

$a=\frac{v-u}{t}$ where u=4 m/s and v=0 m/s

9. mayankdevnani Group Title

find accleration?

10. DLS Group Title

why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change

11. mayankdevnani Group Title

no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS

12. mayankdevnani Group Title

Given u=4 m/s v=0 m/s t=2 s a=v-u/t a=0-4/2 so find acceleration? can you @DLS

13. mayankdevnani Group Title

@DLS

14. DLS Group Title

oh dw I gt it!!

15. mayankdevnani Group Title

ok