• DLS

A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

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  • DLS

A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

Physics
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is answer is 4N
  • DLS
how
  • DLS
yes

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Other answers:

first, find acceleration of body is what is the formula of acceleration of a body???
  • DLS
a=v-u/t
  • DLS
arent v & u both4?
no?
\[a=\frac{v-u}{t}\] where u=4 m/s and v=0 m/s
find accleration?
  • DLS
why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change
no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS
Given u=4 m/s v=0 m/s t=2 s a=v-u/t a=0-4/2 so find acceleration? can you @DLS
  • DLS
oh dw I gt it!!
ok

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