DLS

A body of mass 2 kg, moving on a horizontal surface
with an initial velocity of 4 m/s, comes to rest after 2
seconds. If one wants to keep this body moving on
the same surface with a velocity of 4 m/s, the force
required is

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mayankdevnani

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is answer is 4N

DLS

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how

DLS

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yes

mayankdevnani

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first, find acceleration of body is
what is the formula of acceleration of a body???

DLS

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a=v-u/t

DLS

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arent v & u both4?

mayankdevnani

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no?

mayankdevnani

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\[a=\frac{v-u}{t}\]
where u=4 m/s and v=0 m/s

mayankdevnani

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find accleration?

DLS

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why?
they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change

mayankdevnani

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no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) .
ok @DLS

mayankdevnani

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Given
u=4 m/s
v=0 m/s
t=2 s
a=v-u/t
a=0-4/2
so find acceleration? can you @DLS

mayankdevnani

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@DLS

DLS

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oh dw I gt it!!

mayankdevnani

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ok