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DLS

  • 2 years ago

A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

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  1. mayankdevnani
    • 2 years ago
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    is answer is 4N

  2. DLS
    • 2 years ago
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    how

  3. DLS
    • 2 years ago
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    yes

  4. mayankdevnani
    • 2 years ago
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    first, find acceleration of body is what is the formula of acceleration of a body???

  5. DLS
    • 2 years ago
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    a=v-u/t

  6. DLS
    • 2 years ago
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    arent v & u both4?

  7. mayankdevnani
    • 2 years ago
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    no?

  8. mayankdevnani
    • 2 years ago
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    \[a=\frac{v-u}{t}\] where u=4 m/s and v=0 m/s

  9. mayankdevnani
    • 2 years ago
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    find accleration?

  10. DLS
    • 2 years ago
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    why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change

  11. mayankdevnani
    • 2 years ago
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    no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS

  12. mayankdevnani
    • 2 years ago
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    Given u=4 m/s v=0 m/s t=2 s a=v-u/t a=0-4/2 so find acceleration? can you @DLS

  13. mayankdevnani
    • 2 years ago
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    @DLS

  14. DLS
    • 2 years ago
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    oh dw I gt it!!

  15. mayankdevnani
    • 2 years ago
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    ok

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