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DLS

A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

  • one year ago
  • one year ago

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  1. mayankdevnani
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    is answer is 4N

    • one year ago
  2. DLS
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    how

    • one year ago
  3. DLS
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    yes

    • one year ago
  4. mayankdevnani
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    first, find acceleration of body is what is the formula of acceleration of a body???

    • one year ago
  5. DLS
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    a=v-u/t

    • one year ago
  6. DLS
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    arent v & u both4?

    • one year ago
  7. mayankdevnani
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    no?

    • one year ago
  8. mayankdevnani
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    \[a=\frac{v-u}{t}\] where u=4 m/s and v=0 m/s

    • one year ago
  9. mayankdevnani
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    find accleration?

    • one year ago
  10. DLS
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    why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change

    • one year ago
  11. mayankdevnani
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    no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS

    • one year ago
  12. mayankdevnani
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    Given u=4 m/s v=0 m/s t=2 s a=v-u/t a=0-4/2 so find acceleration? can you @DLS

    • one year ago
  13. mayankdevnani
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    @DLS

    • one year ago
  14. DLS
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    oh dw I gt it!!

    • one year ago
  15. mayankdevnani
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    ok

    • one year ago
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