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DLS
Group Title
A body of mass 2 kg, moving on a horizontal surface
with an initial velocity of 4 m/s, comes to rest after 2
seconds. If one wants to keep this body moving on
the same surface with a velocity of 4 m/s, the force
required is
 one year ago
 one year ago
DLS Group Title
A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is
 one year ago
 one year ago

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mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
is answer is 4N
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
first, find acceleration of body is what is the formula of acceleration of a body???
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
arent v & u both4?
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
\[a=\frac{vu}{t}\] where u=4 m/s and v=0 m/s
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
find accleration?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
Given u=4 m/s v=0 m/s t=2 s a=vu/t a=04/2 so find acceleration? can you @DLS
 one year ago

mayankdevnani Group TitleBest ResponseYou've already chosen the best response.2
@DLS
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
oh dw I gt it!!
 one year ago
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