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## DLS 2 years ago A body of mass 2 kg, moving on a horizontal surface with an initial velocity of 4 m/s, comes to rest after 2 seconds. If one wants to keep this body moving on the same surface with a velocity of 4 m/s, the force required is

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1. mayankdevnani

is answer is 4N

2. DLS

how

3. DLS

yes

4. mayankdevnani

first, find acceleration of body is what is the formula of acceleration of a body???

5. DLS

a=v-u/t

6. DLS

arent v & u both4?

7. mayankdevnani

no?

8. mayankdevnani

$a=\frac{v-u}{t}$ where u=4 m/s and v=0 m/s

9. mayankdevnani

find accleration?

10. DLS

why? they are saying initial and final velocities should be same..i.e 4m/s it shouldnt change

11. mayankdevnani

no, your question said that initial velocity is 4 m/s( written in your question) and final velocity is 0 m/s(comes to rest) . ok @DLS

12. mayankdevnani

Given u=4 m/s v=0 m/s t=2 s a=v-u/t a=0-4/2 so find acceleration? can you @DLS

13. mayankdevnani

@DLS

14. DLS

oh dw I gt it!!

15. mayankdevnani

ok

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