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hbaBest ResponseYou've already chosen the best response.4
Let me show you a trick differentiate \[e ^{x}sinx\] the differential would be \[e^x(sinx+cosx)\] You just take the e^x out of the bracket and then write sinx and then diffrentiate it and write what comes. Let me show you another example differentiate \[e^x tanx\] the differential would be \[e^x(tanx+\sec^2x) \] In this case you also leave the e^x and then write tanx in the bracket and then diffrentiate it and you get sec^2x Let us form a general formula out of it. \[e^x x\] so to diffrentiate it \[e^x(x+\frac{ d(x) }{ dx })\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
\([e^xf(x)]'=e^x(f(x)+f'(x))\) works only for e^x, not for \(e^{ax}\).
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
\([e^{ax}f(x)]'=e^x(af(x)+f'(x))\)
 one year ago

ethompsonnBest ResponseYou've already chosen the best response.0
to much smart ppl, must go dumb down..
 one year ago

DLSBest ResponseYou've already chosen the best response.0
that is the original way how i do it lol :D
 one year ago

hbaBest ResponseYou've already chosen the best response.4
Well i was taught this as a trick lol :D
 one year ago
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