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hba
 2 years ago
Best ResponseYou've already chosen the best response.5Let me show you a trick differentiate \[e ^{x}sinx\] the differential would be \[e^x(sinx+cosx)\] You just take the e^x out of the bracket and then write sinx and then diffrentiate it and write what comes. Let me show you another example differentiate \[e^x tanx\] the differential would be \[e^x(tanx+\sec^2x) \] In this case you also leave the e^x and then write tanx in the bracket and then diffrentiate it and you get sec^2x Let us form a general formula out of it. \[e^x x\] so to diffrentiate it \[e^x(x+\frac{ d(x) }{ dx })\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2\([e^xf(x)]'=e^x(f(x)+f'(x))\) works only for e^x, not for \(e^{ax}\).

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2\([e^{ax}f(x)]'=e^x(af(x)+f'(x))\)

ethompsonn
 2 years ago
Best ResponseYou've already chosen the best response.0to much smart ppl, must go dumb down..

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0that is the original way how i do it lol :D

hba
 2 years ago
Best ResponseYou've already chosen the best response.5Well i was taught this as a trick lol :D
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