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lyzzy7

  • 2 years ago

What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)? y = 3x + 1 y = x – 3 y = 2x + 5 y = 2x – 5

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  1. campbell_st
    • 2 years ago
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    can you find the slope of the line...?

  2. __assassin__
    • 2 years ago
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    http://www.algebra.com/algebra/homework/absolute-value/absolute-value.faq.question.174831.html this should help

  3. lyzzy7
    • 2 years ago
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    yes its -2

  4. __assassin__
    • 2 years ago
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    well then just plot one of your points and keep using your slope.. down two, right one, point. down two right one point. or vice versa up two, left one, point

  5. __assassin__
    • 2 years ago
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    then use slope int. form y=mx+b where m=slope and b=y-int.

  6. campbell_st
    • 2 years ago
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    ok, so the slope intercept form of a line is \[y = mx + b\] and using your slope you have y = -2x + b so to find b pick a point (3, 1) and substitute x = 3 and y = 1 to find b. then you'll have the equation of the line.

  7. lyzzy7
    • 2 years ago
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    so b=7?

  8. campbell_st
    • 2 years ago
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    but looking at your choices... your slope calculation is incorrect... (1 - -3)/(3 - 1)

  9. lyzzy7
    • 2 years ago
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    ohh...

  10. campbell_st
    • 2 years ago
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    lets get the slope right 1st

  11. lyzzy7
    • 2 years ago
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    I still got -2..

  12. lyzzy7
    • 2 years ago
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    1- (-3) = -4. 3-1= 2. so thats -4/2, simplified to -2/1= -2

  13. campbell_st
    • 2 years ago
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    1 - -3 = 4 2 negatives make a positive so the slope is 4/2 or 2 so you have y = 2x + b substitute x = 3, y = 1 to find b and the equation of your line

  14. lyzzy7
    • 2 years ago
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    so b= -5?

  15. campbell_st
    • 2 years ago
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    thats it so your line is y = 2x - 5

  16. lyzzy7
    • 2 years ago
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    omg thank you:D <3333

  17. campbell_st
    • 2 years ago
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    glad to help

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