What is an equation in slope-intercept form for the line that passes through the points (1, –3) and (3, 1)?
y = 3x + 1
y = x – 3
y = 2x + 5
y = 2x – 5
Stacey Warren - Expert brainly.com
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can you find the slope of the line...?
http://www.algebra.com/algebra/homework/absolute-value/absolute-value.faq.question.174831.html this should help
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well then just plot one of your points and keep using your slope.. down two, right one, point. down two right one point. or vice versa up two, left one, point
then use slope int. form y=mx+b where m=slope and b=y-int.
ok, so the slope intercept form of a line is
\[y = mx + b\]
and using your slope you have
y = -2x + b
so to find b pick a point (3, 1) and substitute x = 3 and y = 1 to find b.
then you'll have the equation of the line.
but looking at your choices... your slope calculation is incorrect...
(1 - -3)/(3 - 1)
lets get the slope right 1st
I still got -2..
1- (-3) = -4. 3-1= 2. so thats -4/2, simplified to -2/1= -2
1 - -3 = 4 2 negatives make a positive
so the slope is 4/2 or 2
so you have
y = 2x + b substitute x = 3, y = 1
to find b and the equation of your line