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What forces act on the block with mass m2 (as seen on the picture)?
Gravity for sure but I guess the cylinder does also something. Perhaps Tension plays also some role?
 one year ago
 one year ago
What forces act on the block with mass m2 (as seen on the picture)? Gravity for sure but I guess the cylinder does also something. Perhaps Tension plays also some role?
 one year ago
 one year ago

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TomLikesPhysicsBest ResponseYou've already chosen the best response.0
The cylinder can rotate without friction and is fixed there. The moment of inertia of the cylinder is 1/2*M1*R^2.
 one year ago

cheesesticksBest ResponseYou've already chosen the best response.0
gravity and friction
 one year ago

cheesesticksBest ResponseYou've already chosen the best response.0
tension is like tug of war
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Sry, I forgot to mention that there is no friction.^^
 one year ago

cheesesticksBest ResponseYou've already chosen the best response.0
o is it multiple choice?
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
Weight, normal force, tension in the rope.
 one year ago

cheesesticksBest ResponseYou've already chosen the best response.0
WAIT THATS A ROPE?
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.3
dw:1354312298270:dw
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
That seems perfect!
 one year ago

mahmit2012Best ResponseYou've already chosen the best response.3
dw:1354312672595:dw
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Do you mean with T the Tension or Torque? If you mean Tension  why is T*R=I*alpha?
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
T is tension. Torque is: \(\large \tau\normalsize=TR\)
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
So the moment of inertia of the cylinder is connected with the tension... I have never seen this formula: T=I*alpha. Where does it come from? Normally Torque = Moment of Inertia * angular acceleration but now you say it also equals a force (tension)? I think the units do not add up because normally I*alpha gives you "Nm" and not "N".
 one year ago

shamimBest ResponseYou've already chosen the best response.0
\[m _{2}gsin \theta T=m _{2}a\]
 one year ago

shamimBest ResponseYou've already chosen the best response.0
\[R=m _{2}gcos \theta\]
 one year ago

shamimBest ResponseYou've already chosen the best response.0
R is a force acted by the surface on the body of mass m2
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
I don't think anybody wrote : T=I*alpha, where T is a tension. This is dimensionnaly wrong. Equivalent of N's 2nd law for rotating bodies is: net torque \(\Large \tau\) = \(I\;\alpha\)
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
@shamim careful, R is the radius of the pulley. The problem has already been solved by mahmit2012
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Ok, but why is T*R=I*alpha? I only saw this guy when T meant Torque so I have no clue where mahmit2012 got it from.
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
Because torque acting on the pulley is the moment of the force \(\vec T\) about the axis of the pulley. Moment of \(\vec T\) is simply \(RT\) because \(\vec T\) acts at right angles to the radius of the pulley.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Oh ... Torque = radius cross Force. Here the force on the cylinder is the tension. Also Torque equals moment of Inertia times alpha.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
k, I think I get it now. Thanks a lot VincentLycon.Fr and mahmit2012.
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
yw :)) goodbye!
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
A shame that I can not get you booth a "Best Response". mahmit2012 solved the thing but you (VincentLyon.Fr) explained it further.
 one year ago

VincentLyon.FrBest ResponseYou've already chosen the best response.0
NP, mahmit deserves the award.
 one year ago
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