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anonymous
 4 years ago
What forces act on the block with mass m2 (as seen on the picture)?
Gravity for sure but I guess the cylinder does also something. Perhaps Tension plays also some role?
anonymous
 4 years ago
What forces act on the block with mass m2 (as seen on the picture)? Gravity for sure but I guess the cylinder does also something. Perhaps Tension plays also some role?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The cylinder can rotate without friction and is fixed there. The moment of inertia of the cylinder is 1/2*M1*R^2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tension is like tug of war

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sry, I forgot to mention that there is no friction.^^

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0o is it multiple choice?

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0Weight, normal force, tension in the rope.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1354312298270:dw

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0That seems perfect!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1354312672595:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you mean with T the Tension or Torque? If you mean Tension  why is T*R=I*alpha?

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0T is tension. Torque is: \(\large \tau\normalsize=TR\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the moment of inertia of the cylinder is connected with the tension... I have never seen this formula: T=I*alpha. Where does it come from? Normally Torque = Moment of Inertia * angular acceleration but now you say it also equals a force (tension)? I think the units do not add up because normally I*alpha gives you "Nm" and not "N".

shamim
 4 years ago
Best ResponseYou've already chosen the best response.0\[m _{2}gsin \theta T=m _{2}a\]

shamim
 4 years ago
Best ResponseYou've already chosen the best response.0R is a force acted by the surface on the body of mass m2

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0I don't think anybody wrote : T=I*alpha, where T is a tension. This is dimensionnaly wrong. Equivalent of N's 2nd law for rotating bodies is: net torque \(\Large \tau\) = \(I\;\alpha\)

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0@shamim careful, R is the radius of the pulley. The problem has already been solved by mahmit2012

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, but why is T*R=I*alpha? I only saw this guy when T meant Torque so I have no clue where mahmit2012 got it from.

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0Because torque acting on the pulley is the moment of the force \(\vec T\) about the axis of the pulley. Moment of \(\vec T\) is simply \(RT\) because \(\vec T\) acts at right angles to the radius of the pulley.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh ... Torque = radius cross Force. Here the force on the cylinder is the tension. Also Torque equals moment of Inertia times alpha.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k, I think I get it now. Thanks a lot VincentLycon.Fr and mahmit2012.

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0yw :)) goodbye!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A shame that I can not get you booth a "Best Response". mahmit2012 solved the thing but you (VincentLyon.Fr) explained it further.

VincentLyon.Fr
 4 years ago
Best ResponseYou've already chosen the best response.0NP, mahmit deserves the award.
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