there are 17 questions on a moodle test, each of which consists of randomly drawing from three possible questions. how many different tests are possible? if two students take the exam, what is the probability that they will take the same exam?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

- anonymous

- jamiebookeater

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

I pretty sure that the number of tests is 3^17 = 129,140,163. I have noooo clue how to approach the problem of probability though...

- anonymous

You're right about the number of tests.

- anonymous

Given that it's arbitrary which questions they choose, call test A (the test that No.1 takes), say that A=(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1)
Now, we've defined person 1 as choosing (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1), so the prob of that happening is =1.
The probability of person 2 choosing (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1) , however, is 1/(129,140,163), as there are 129,140,163-1 different tests they could have chosen

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

do you mean 1/129,140,162? and that is the probability of persons 1 & 2 getting the same test? or do i have to multiply the probabilities for persons 1 & 2 together for that?

- anonymous

That is the probability, yes. I have already multiplied them together, as the prob of person 1 getting the same test as person 1 is 100%

- anonymous

1/129,140,162 is the probability of them getting the same test then? Okay, I'll take your word for it. I have a really really hard time wrapping my mind around these types of questions and the associated math, they never seem to make a lot of sense to me. Thanks for your help! ^_^

- anonymous

OK. The key thing is that it's irrelevant WHICH test the first person chooses, just that the 2nd person's choice matches the 1st's

Looking for something else?

Not the answer you are looking for? Search for more explanations.