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em.denning Group Title

there are 17 questions on a moodle test, each of which consists of randomly drawing from three possible questions. how many different tests are possible? if two students take the exam, what is the probability that they will take the same exam?

  • one year ago
  • one year ago

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  1. em.denning Group Title
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    I pretty sure that the number of tests is 3^17 = 129,140,163. I have noooo clue how to approach the problem of probability though...

    • one year ago
  2. henpen Group Title
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    You're right about the number of tests.

    • one year ago
  3. henpen Group Title
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    Given that it's arbitrary which questions they choose, call test A (the test that No.1 takes), say that A=(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1) Now, we've defined person 1 as choosing (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1), so the prob of that happening is =1. The probability of person 2 choosing (1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1) , however, is 1/(129,140,163), as there are 129,140,163-1 different tests they could have chosen

    • one year ago
  4. em.denning Group Title
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    do you mean 1/129,140,162? and that is the probability of persons 1 & 2 getting the same test? or do i have to multiply the probabilities for persons 1 & 2 together for that?

    • one year ago
  5. henpen Group Title
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    That is the probability, yes. I have already multiplied them together, as the prob of person 1 getting the same test as person 1 is 100%

    • one year ago
  6. em.denning Group Title
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    1/129,140,162 is the probability of them getting the same test then? Okay, I'll take your word for it. I have a really really hard time wrapping my mind around these types of questions and the associated math, they never seem to make a lot of sense to me. Thanks for your help! ^_^

    • one year ago
  7. henpen Group Title
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    OK. The key thing is that it's irrelevant WHICH test the first person chooses, just that the 2nd person's choice matches the 1st's

    • one year ago
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