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saifoo.khan

  • 3 years ago

Please check my answers:

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  1. breja
    • 3 years ago
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    What answers?

  2. saifoo.khan
    • 3 years ago
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    Q14 (c) and (d)

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  3. BluFoot
    • 3 years ago
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    You mean 14 i and ii? There's no (c) and (d). I got 1/25 for i and 1/5 for ii

  4. saifoo.khan
    • 3 years ago
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    Oh wait. Q13 (c) and (d)

  5. saifoo.khan
    • 3 years ago
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    And how you got that for Q14?

  6. BluFoot
    • 3 years ago
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    13C I got 10/16 and 13D I got 14/16

  7. BluFoot
    • 3 years ago
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    Oops meant 1/5 for 14 i

  8. BluFoot
    • 3 years ago
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    There are 25 possibilities right? 0 then 0, or 0 then 1, or 0 then 2 etc. 5 of them have the same number on both days: (0,0), (1,1), (2,2), (3,3), (4,4). So the probability is 5/25=1/5.

  9. BluFoot
    • 3 years ago
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    Same idea with 14 ii. There are 25 possibilities. 5 of them have a total of 4: (0,4), (1,3), (2,2), (3,1), (4,0)

  10. saifoo.khan
    • 3 years ago
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    I got right for 13(c).

  11. saifoo.khan
    • 3 years ago
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    And for (d) too

  12. saifoo.khan
    • 3 years ago
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    I don't get 14 one. Sorry. :/

  13. BluFoot
    • 3 years ago
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    Make a probability tree with all the possibilites if you want. Like this, except there should 0,1,2,3,4 at the end of each of the 5 branches. |dw:1354320893329:dw| You can see there are 25 possibilities. How many of them have the same number on each day?

  14. saifoo.khan
    • 3 years ago
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    |dw:1354321015621:dw|

  15. BluFoot
    • 3 years ago
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    There's one of them. Except you did the probability wrong, it's 1/5=0.2 not 0.1.

  16. saifoo.khan
    • 3 years ago
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    No. In the table it's given 0.1

  17. BluFoot
    • 3 years ago
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    OOOHHHHHH I completely forgot about the probabilities!! I'm sorry :P I was assuming each day had the same probability! I'll look at it again

  18. saifoo.khan
    • 3 years ago
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    No problem. Sure. :)

  19. BluFoot
    • 3 years ago
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    Yeah so you're on the right track. The probability of 4 on each day is 0.1*0.1=0.01. Now do the same for the other numbers.

  20. saifoo.khan
    • 3 years ago
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    Perfect. What about part(ii) ?

  21. BluFoot
    • 3 years ago
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    Now you want to look at all the possibilites that add up to 4. So: (0,4), (1,3), (2,2), (3,1) and (4,0) Find the probabilities of each of those and add them together.

  22. saifoo.khan
    • 3 years ago
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    Got'ya. Thanks a ton.

  23. angelpatterson
    • 3 years ago
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    Ok well that's a really long conversation.Why isn't it closed?

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