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gerryliyanaBest ResponseYou've already chosen the best response.2
The solution for Forced Harmonic motion is given by: \[Q = Q_{1}e^{\left( (R/2L)+\sqrt{(R/2L)^{2}  \omega_{o}^{2}} \right)t} + Q_{2}e^{\left( (R/2L)  \sqrt{(R/2L)^{2}\omega_{o}^{2}} \right)t} \] If \(Q = A \cos \theta \) and \(\frac{ dQ }{ dt } \approx \omega A \sin \theta t\) at t =0, also known that \(R/L \approx 0 \) and \(\theta \approx \pi/2\) Find the value of Q1 and Q2! Hbu???
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.2
i got Q1=Q2 = 1/2 A cos theta.,
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.2
how to draw a graph Q vs t with quantitative data??
 one year ago

ghaziBest ResponseYou've already chosen the best response.2
yess its correct and to draw graph you can either draw on graph paper with neumerical value or you can use logarithmic graph paper
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.2
very nice, thank u., ok i'll try..,
 one year ago
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