A community for students.
Here's the question you clicked on:
 0 viewing
DLS
 2 years ago
If "this" is true,then prove that (x^2y^2+3)dy/dx=1
DLS
 2 years ago
If "this" is true,then prove that (x^2y^2+3)dy/dx=1

This Question is Closed

Kelumptus
 2 years ago
Best ResponseYou've already chosen the best response.0is that x+1/n+1/x+1/x to infinity?

Kelumptus
 2 years ago
Best ResponseYou've already chosen the best response.0I see what you mean but now that I understand the question I would have to say that I am not sure either :/. Hopefully someone more knowledgeable than myself looks at this...

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0Here's the printed question,just if its not clear

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0If "this" is true,then prove that (x^2y^2+3)dy/dx=1

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0To prove: \[(x^{2}y^{2}+3)\frac{dy}{dx}=1\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1use this \[Y=X+\frac{ 1 }{ Y }\]

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2the given equation \[\large y=x+\frac{ 1 }{ x+\frac{ 1 }{ x+... } }\] is equivalent to \[\large y=x+\frac{ 1 }{ y }\]

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2find the derivative by implicit differentiation

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1also you can substitute x at the place where you have to prove a desired result

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0please ellaborate,I'm doing this type of question first time

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large y = x+\frac{ 1 }{ \left[ x+\frac{ 1 }{ x+... } \right] }=x+\frac{ 1 }{ y }\] because the bracketed expression is equal to y

Kelumptus
 2 years ago
Best ResponseYou've already chosen the best response.0Ahh, that's clever sirm3d, makes sense now. I couldn't figure this one out.

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2just take the derivative of both sides by implicit differentiation. the derivative of the LHS is \[\large (dy/dx)\] the derivative of the RHS is 1 

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1LHS  left hand side RHS right hand side

Kelumptus
 2 years ago
Best ResponseYou've already chosen the best response.0Here is a good reference for implicit differentiation: http://www.intmath.com/differentiation/8derivativeimplicitfunction.php

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2oops, the derivative of the RHS is \[\large 1  \frac{ 1 }{ y^2 }(dy/dx)\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1@DLS i guess you can do it now

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large \frac{ 1 }{ y }=y^{1}\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1he differentiated it , implicitly

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy (x^n) }{ dx }=nx^{n1}\]

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2by power rule and chain rule, the derivative of y^(1) is \[1y^{2} \frac{ dy }{ dx }\]

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.2equate the derivative of the LHS to the derivative of the RHS, then group terms with (dy/dx)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.