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DLS Group TitleBest ResponseYou've already chosen the best response.0
dw:1354339128951:dw
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
is that x+1/n+1/x+1/x to infinity?
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
I see what you mean but now that I understand the question I would have to say that I am not sure either :/. Hopefully someone more knowledgeable than myself looks at this...
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
Here's the printed question,just if its not clear
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
If "this" is true,then prove that (x^2y^2+3)dy/dx=1
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
To prove: \[(x^{2}y^{2}+3)\frac{dy}{dx}=1\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
@Algebraic! @ghazi @RadEn
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
use this \[Y=X+\frac{ 1 }{ Y }\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
the given equation \[\large y=x+\frac{ 1 }{ x+\frac{ 1 }{ x+... } }\] is equivalent to \[\large y=x+\frac{ 1 }{ y }\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
find the derivative by implicit differentiation
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
also you can substitute x at the place where you have to prove a desired result
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
please ellaborate,I'm doing this type of question first time
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
\[\large y = x+\frac{ 1 }{ \left[ x+\frac{ 1 }{ x+... } \right] }=x+\frac{ 1 }{ y }\] because the bracketed expression is equal to y
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
yeah i got that,what next
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
Ahh, that's clever sirm3d, makes sense now. I couldn't figure this one out.
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
just take the derivative of both sides by implicit differentiation. the derivative of the LHS is \[\large (dy/dx)\] the derivative of the RHS is 1 
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
LHS  left hand side RHS right hand side
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
lol i know that
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
Here is a good reference for implicit differentiation: http://www.intmath.com/differentiation/8derivativeimplicitfunction.php
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
oops, the derivative of the RHS is \[\large 1  \frac{ 1 }{ y^2 }(dy/dx)\]
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
@DLS i guess you can do it now
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
what did u do with 1/y
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
\[\large \frac{ 1 }{ y }=y^{1}\]
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
he differentiated it , implicitly
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
how did u get y^2
 one year ago

ghazi Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ dy (x^n) }{ dx }=nx^{n1}\]
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
by power rule and chain rule, the derivative of y^(1) is \[1y^{2} \frac{ dy }{ dx }\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
i know that too ! :o
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
okay whats the last step?
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.2
equate the derivative of the LHS to the derivative of the RHS, then group terms with (dy/dx)
 one year ago
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