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de.nira
Group Title
Renting video games from The Video Vendor costs
6 dollars per game with no annual membership fee.
Renting video games from the Game Garage
costs 3 dollars per game, but a customer must
pay an additional $60 for an annual membership.
If n represents the number of video games a
customer rents in a year, which of the following
gives all values of n for which it costs less to rent
from the Game Garage than from the Video
Vendor?
The options are (a) n < 10, (b) n = 10, (c) 10 < n < 20, (d) n = 20, (e) n > 20
 one year ago
 one year ago
de.nira Group Title
Renting video games from The Video Vendor costs 6 dollars per game with no annual membership fee. Renting video games from the Game Garage costs 3 dollars per game, but a customer must pay an additional $60 for an annual membership. If n represents the number of video games a customer rents in a year, which of the following gives all values of n for which it costs less to rent from the Game Garage than from the Video Vendor? The options are (a) n < 10, (b) n = 10, (c) 10 < n < 20, (d) n = 20, (e) n > 20
 one year ago
 one year ago

This Question is Open

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
So a good starting point for this one is to ask, what is the break even point?
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
To find the break even point you need to look at this problem as a simultaneous equation.
 one year ago

Kelumptus Group TitleBest ResponseYou've already chosen the best response.0
The easiest way to solve a simple simultaneous equation like this is to equate both equations and solve for x. For instance: Video Vender cost function = Game Garage cost function (where for each of these functions, x represents the number of videos per yer. Solving for x gives the break even point (you can also visualize this as being the point where the 2 functions intersect if you were to graph them together). Once you have this 'break even' point, the answer should be obvious.
 one year ago
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