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DLS
 2 years ago
Best ResponseYou've already chosen the best response.1\[y=\log(x^{2}\sqrt{x^{2}+1})\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1I got something like this \[\frac{1}{x^{2}\sqrt{x^{2}+1}} \times 2\sqrt{x^{2}+1} \times 2x\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4there is a bit of editing you should have used product rule

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d(x^2 \sqrt{x^2+1}) }{ dx }=x^2\frac{ d \sqrt{x^2+1} }{ dx }+\sqrt{x^2+1}*2x\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1how did you get dx in the denominator?

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4you are differentiating with respect to x

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4i can write it as\[\frac{ d }{ dx }(\sqrt{x^2+1}*x^2)\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1oh wait equation is messed up lol just asec

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{dy}{dx}=\frac{dlog(x^{2}\sqrt{x^{2}+1}}{dx^{2}\sqrt{x^{2}+1}} \times \frac{dx^{2} \sqrt{x^{2}+1}}{d \sqrt{x^{2}+1}} \] ..so on

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1i do like this,where i didnt diff. wrt. dx

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4you have to differentiate wrt x, you can't diffrentiate wrt to function

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1wth :/ am i taught wrong :S but i was getting all the answers like this

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4differentiation is done wrt to a variable basically differentiation tells us rate of change of one variable wrt to another and function is something that tells us the relation between those two variables so we can never get rate of change wrt to a function

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d }{ dx }(\sqrt{x^2+1})*x^2+2x* \sqrt{x^2+1}\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{ 1 }{ \sqrt{x^2+1} }*\frac{ d }{ dx }(x^2+1)\]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4there will be a factor of 1/2 multiplied in RHS

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1derivative of sqrt x is 1/2x right :o

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{d \sqrt{x}}{dx}= \frac{1}{2 \sqrt{x}}\] does my coaching class suck lol :/

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1http://wiki.answers.com/Q/What_is_the_derivative_of_square_root_of_x

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4no they are right let me show you

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1will it be like this: \[\frac{1}{2 \sqrt{x^{2}+1}} \times 2x = \frac{x}{\sqrt{x^{2}+1}} \]

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d }{ dx } (x)^{1/2}= \frac{ 1 }{ 2 }(x)^{1/21}\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1so how do we have 2 answers

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4no we have one, just be careful in calculating power

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1so final answer im getting is

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{x^{2} \sqrt{x^{2}+1}} \times \frac{x}{\sqrt{x^{2}+1}}\]

DLS
 2 years ago
Best ResponseYou've already chosen the best response.1which is wrong :/ http://www.wolframalpha.com/input/?i=derivative+of+log%28x%5E2%28sqrt%28x%5E2%2B1%29%29%29

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{1 }{ 2 }(\sqrt{x^2+1})^{3/2}* 2x\] your answer

ghazi
 2 years ago
Best ResponseYou've already chosen the best response.4\[\frac{ d }{ dx }(x^n)=nx^{n1}\] hope you know this formula
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