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DLS Group Title

DE help

  • one year ago
  • one year ago

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  1. DLS Group Title
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    \[y=\log(x^{2}\sqrt{x^{2}+1})\]

    • one year ago
  2. DLS Group Title
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    I got something like this \[\frac{1}{x^{2}\sqrt{x^{2}+1}} \times 2\sqrt{x^{2}+1} \times 2x\]

    • one year ago
  3. DLS Group Title
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    @ghazi

    • one year ago
  4. ghazi Group Title
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    there is a bit of editing you should have used product rule

    • one year ago
  5. ghazi Group Title
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    for (x^2 sqrt{x^2+1})

    • one year ago
  6. DLS Group Title
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    how?:o

    • one year ago
  7. ghazi Group Title
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    \[\frac{ d(x^2 \sqrt{x^2+1}) }{ dx }=x^2\frac{ d \sqrt{x^2+1} }{ dx }+\sqrt{x^2+1}*2x\]

    • one year ago
  8. DLS Group Title
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    woah :o thanks

    • one year ago
  9. ghazi Group Title
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    :) YW

    • one year ago
  10. DLS Group Title
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    how did you get dx in the denominator?

    • one year ago
  11. ghazi Group Title
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    you are differentiating with respect to x

    • one year ago
  12. ghazi Group Title
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    i can write it as\[\frac{ d }{ dx }(\sqrt{x^2+1}*x^2)\]

    • one year ago
  13. DLS Group Title
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    oh wait equation is messed up lol just asec

    • one year ago
  14. DLS Group Title
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    \[\frac{dy}{dx}=\frac{dlog(x^{2}\sqrt{x^{2}+1}}{dx^{2}\sqrt{x^{2}+1}} \times \frac{dx^{2} \sqrt{x^{2}+1}}{d \sqrt{x^{2}+1}} \] ..so on

    • one year ago
  15. ghazi Group Title
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    NO

    • one year ago
  16. DLS Group Title
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    i do like this,where i didnt diff. wrt. dx

    • one year ago
  17. DLS Group Title
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    thats how im taught >.>

    • one year ago
  18. ghazi Group Title
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    you have to differentiate wrt x, you can't diffrentiate wrt to function

    • one year ago
  19. DLS Group Title
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    wth :/ am i taught wrong :S but i was getting all the answers like this

    • one year ago
  20. ghazi Group Title
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    differentiation is done wrt to a variable basically differentiation tells us rate of change of one variable wrt to another and function is something that tells us the relation between those two variables so we can never get rate of change wrt to a function

    • one year ago
  21. DLS Group Title
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    okay..!

    • one year ago
  22. ghazi Group Title
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    \[\frac{ d }{ dx }(\sqrt{x^2+1})*x^2+2x* \sqrt{x^2+1}\]

    • one year ago
  23. DLS Group Title
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    okay...clear!

    • one year ago
  24. ghazi Group Title
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    cool :D

    • one year ago
  25. ghazi Group Title
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    \[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{ 1 }{ \sqrt{x^2+1} }*\frac{ d }{ dx }(x^2+1)\]

    • one year ago
  26. ghazi Group Title
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    there will be a factor of -1/2 multiplied in RHS

    • one year ago
  27. DLS Group Title
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    derivative of sqrt x is 1/2x right :o

    • one year ago
  28. ghazi Group Title
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    -1/2 x

    • one year ago
  29. DLS Group Title
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    \[\frac{d \sqrt{x}}{dx}= \frac{1}{2 \sqrt{x}}\] does my coaching class suck lol :/

    • one year ago
  30. DLS Group Title
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    http://wiki.answers.com/Q/What_is_the_derivative_of_square_root_of_x

    • one year ago
  31. ghazi Group Title
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    no they are right let me show you

    • one year ago
  32. DLS Group Title
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    will it be like this: \[\frac{1}{2 \sqrt{x^{2}+1}} \times 2x = \frac{x}{\sqrt{x^{2}+1}} \]

    • one year ago
  33. ghazi Group Title
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    \[\frac{ d }{ dx } (x)^{-1/2}= \frac{ -1 }{ 2 }(x)^{-1/2-1}\]

    • one year ago
  34. DLS Group Title
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    so how do we have 2 answers

    • one year ago
  35. ghazi Group Title
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    no we have one, just be careful in calculating power

    • one year ago
  36. DLS Group Title
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    okay..

    • one year ago
  37. DLS Group Title
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    so final answer im getting is

    • one year ago
  38. DLS Group Title
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    \[\frac{1}{x(x^{2}+1}\]

    • one year ago
  39. DLS Group Title
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    \[\frac{1}{x^{2} \sqrt{x^{2}+1}} \times \frac{x}{\sqrt{x^{2}+1}}\]

    • one year ago
  40. DLS Group Title
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    which is wrong :/ http://www.wolframalpha.com/input/?i=derivative+of+log%28x%5E2%28sqrt%28x%5E2%2B1%29%29%29

    • one year ago
  41. ghazi Group Title
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    \[\frac{ d }{ dx } (\sqrt{x^2+1})=\frac{1 }{ 2 }(\sqrt{x^2+1})^{-3/2}* 2x\] your answer

    • one year ago
  42. DLS Group Title
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    what did you do

    • one year ago
  43. ghazi Group Title
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    \[\frac{ d }{ dx }(x^n)=nx^{n-1}\] hope you know this formula

    • one year ago
  44. DLS Group Title
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    oh okay!

    • one year ago
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