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pratu043 Group Title

The speed of a cycle increases from 2.5 m/s to 5 m/s. The total mass of the cyclist including the cycle is 120 kg. Calculate the work done by the cyclist to increase the speed.

  • one year ago
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  1. shamim Group Title
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    i m trying to solve this problem

    • one year ago
  2. shamim Group Title
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    here u=2.5 v=5 m=120kg work done W=?

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  3. shamim Group Title
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    \[W=FS=maS\]

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  4. shamim Group Title
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    again we know\[v ^{2}=u ^{2}+2aS\]

    • one year ago
  5. shamim Group Title
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    \[or, 2aS=v ^{2}-u ^{2}\]

    • one year ago
  6. shamim Group Title
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    \[or, aS=\frac{ v ^{2}-u ^{2} }{ 2 }\]

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  7. shamim Group Title
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    putting this value of aS in the 1st equation we get

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  8. shamim Group Title
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    \[W=m(\frac{ v ^{2}-u ^{2} }{ 2 })\]

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  9. shamim Group Title
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    \[or, W=120 \times (\frac{ 5^{2}-2.5^{2} }{ 2 })\]

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  10. shamim Group Title
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    or, W=1125 joule

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  11. shamim Group Title
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    r u following me

    • one year ago
  12. Vincent-Lyon.Fr Group Title
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    Use work-energy theorem, and write: \(W=m(\Large\frac{ v ^{2}-u ^{2} }{ 2 })\) directly. This is more general than the derivation provided by shamim, as it will be true even for non-uniform acceleration. But this will only be true if the cyclist is on a horizontal road.

    • one year ago
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