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50% ??

just apply triangle inequality.

your point is ,
sum of two sides of triangle must be > 3rd ?

yaaa

used that, solved it, got 50%
want to verify whether its correct....

verify-
3,3,3(forms triangle)
sum of two sides of triangle must be > 3rd(6>3)

i would like to restate :
sum of two sides of triangle must be > or = 3rd

right

6>3(3+3>3) PROVE IT!

thus, it proves it forms a triangle!!!
@hartnn can you understand??

yes, that forms equilateral triangle. but i want to find the probability.

i think probability is outcome/parts=10/3

probability can never be >1 -_-

You want that 1 of the segments is not >0.5 of the stick.

ofcourse, i got that when i solved, and that gave me 50%.

By what logic?

ok, i'll show what i had done in test.

I'll type up my try to work out a numerical answer at the same time

|dw:1354374054772:dw|

@UnkleRhaukus can u have a look and share any ideas ??
same for Callisto.

isn't this getting complicated ?
for me, yes....
what wrong in my answer ?

yeah, a is fixed.
i will make a triangle with sides x,y,z.

one*

|dw:1354375288008:dw| We want \[p+q<0.5\]

hmm,

huh ?

25% sure ?

fairly sure