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- anonymous

How do I find the total resistance of this network? Somehow I can not figure this simple network out.

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- anonymous

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- anonymous

- anonymous

I know how to deal with resistors that a parallel or in a row but this configuration somehow confuses me.

- anonymous

Hmmmm I ended up with 50/3 Ohms for the total resistance.

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- anonymous

Given that R3=R4, I think no electrons will flow down resistor 5.

- anonymous

But R5 is not as big as R3 so woudn´t some electrons prefer R5 over R3?

- anonymous

But they 'know' (because of repulsion of electrons in front of them, possibly) that R4 exists.

- eSpeX

To find the equivalent resistance for this circuit you need to do a delta|wye conversion and then do your calculations.

- anonymous

I have never heard of a delta wye conversion.

- anonymous

tommy.. this network indeed is very complicated and you need to do a delta conversion .. however
if R1/R3= R2/R4 then the its called a balanced circuit.. and it can be proved that.. no current flows through R5 and you can chuck it!

- anonymous

Ok, but this network ist not a balaced circuit because that resistor-ratio does not fit this network.

- Vincent-Lyon.Fr

Use Δ→Y transform (fast), or use 2 loops and write down all Kirchhoff's circuit laws that apply (slow).
http://en.wikipedia.org/wiki/Delta_Y

- Vincent-Lyon.Fr

You can also remove R5 and use Thevenin's equivalent to find the fictitious generator between those terminals, then put R5 back in again. But this is longer.

- ghazi

using thevnin will give the load voltage and i don't think we can apply thevnin here, if you remove R5 then yes we can think of it

- anonymous

Okay, I used Kirchhoff and got now this:

- anonymous

ok this is out of my league now :D

- ghazi

i guess its 300/11 ohm =27.27 ohm

- anonymous

Are my equations alright?

- Vincent-Lyon.Fr

Answer is 685/24 = 28.54 Ω.

- Vincent-Lyon.Fr

There is a mistake : J5 cannot have a minus sign in eq.1 and eq.2

- Vincent-Lyon.Fr

Besides, I do not understand what UR means. Are you multiplying resistance with voltage? This will not lead you anywhere.

- anonymous

-.- of course. My mistake, the Us have to be Is.
For the Equations one and two I was looking at the nodes in the middle.

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