anonymous
  • anonymous
How do I find the total resistance of this network? Somehow I can not figure this simple network out.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
I know how to deal with resistors that a parallel or in a row but this configuration somehow confuses me.
anonymous
  • anonymous
Hmmmm I ended up with 50/3 Ohms for the total resistance.

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More answers

anonymous
  • anonymous
Given that R3=R4, I think no electrons will flow down resistor 5.
anonymous
  • anonymous
But R5 is not as big as R3 so woudn´t some electrons prefer R5 over R3?
anonymous
  • anonymous
But they 'know' (because of repulsion of electrons in front of them, possibly) that R4 exists.
eSpeX
  • eSpeX
To find the equivalent resistance for this circuit you need to do a delta|wye conversion and then do your calculations.
anonymous
  • anonymous
I have never heard of a delta wye conversion.
anonymous
  • anonymous
tommy.. this network indeed is very complicated and you need to do a delta conversion .. however if R1/R3= R2/R4 then the its called a balanced circuit.. and it can be proved that.. no current flows through R5 and you can chuck it!
anonymous
  • anonymous
Ok, but this network ist not a balaced circuit because that resistor-ratio does not fit this network.
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
Use Δ→Y transform (fast), or use 2 loops and write down all Kirchhoff's circuit laws that apply (slow). http://en.wikipedia.org/wiki/Delta_Y
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
You can also remove R5 and use Thevenin's equivalent to find the fictitious generator between those terminals, then put R5 back in again. But this is longer.
ghazi
  • ghazi
using thevnin will give the load voltage and i don't think we can apply thevnin here, if you remove R5 then yes we can think of it
anonymous
  • anonymous
Okay, I used Kirchhoff and got now this:
1 Attachment
anonymous
  • anonymous
ok this is out of my league now :D
ghazi
  • ghazi
i guess its 300/11 ohm =27.27 ohm
anonymous
  • anonymous
Are my equations alright?
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
Answer is 685/24 = 28.54 Ω.
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
There is a mistake : J5 cannot have a minus sign in eq.1 and eq.2
Vincent-Lyon.Fr
  • Vincent-Lyon.Fr
Besides, I do not understand what UR means. Are you multiplying resistance with voltage? This will not lead you anywhere.
anonymous
  • anonymous
-.- of course. My mistake, the Us have to be Is. For the Equations one and two I was looking at the nodes in the middle.

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