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\[\sin (\pi/3) + \cos (\pi/3)\]

An entry level explanation would be useful.

Pi/3=60º
as is well known cos60º=1/2 and sin60º=sqrt3/2

Should I have converted them to degrees then?

if it is more clear for you, then yes, if not just stay with radians

corresponding to \(\frac{\pi}{3}\)

alright I see an ordered pair that looks suspiciously like sin and cos that you mentioned earlier

So what if this is on a test and I'm not allowed the cheat sheet?

(The ones they ask me to solve without a calculator.)