## anonymous 3 years ago Evaluate the expression without using a calculator.

1. anonymous

$\sin (\pi/3) + \cos (\pi/3)$

2. anonymous

An entry level explanation would be useful.

3. anonymous

Pi/3=60º as is well known cos60º=1/2 and sin60º=sqrt3/2

4. anonymous

5. anonymous

Should I have converted them to degrees then?

6. anonymous

allow me to disagree with @myko this question has nothing to do with degrees. forget degrees it has to do with numbers find the sine and cosine from the coordinates on the unit circle

7. anonymous

if it is more clear for you, then yes, if not just stay with radians

8. anonymous

do not start a trig problem by converting numbers to degrees, it is a bad habit and will mess you up later if you are working with numbers, stick with numbers

9. anonymous

degrees are just, sometimes, more evident to place a apoint in the circle. But I agree with @satellite73 that it is more strait with rad

10. anonymous

sine and cosine are functions of numbers, not angles. they correspond to the functions of angles if the angles are measured in radians

11. anonymous

alright that seems to make sense. Will you walk me through what you mean by "find the sine and cosine from the coordinates on the unit circle?"

12. anonymous

look at the last page of the cheat sheet i sent locate the point on the unit circle corresponding to $$\frac{\pi}{3}$$ 2x ^{5}+x ^{3}-7x+14

13. anonymous

corresponding to $$\frac{\pi}{3}$$

14. anonymous

alright I see an ordered pair that looks suspiciously like sin and cos that you mentioned earlier

15. anonymous

you should see the ordered pair $$(\frac{1}{2},\frac{\sqrt{3}}{2})$$ the first coordinate is $$\cos(\frac{\pi}{3})$$ and the second coordinate is $$\sin(\frac{\pi}{3})$$

16. anonymous

So what if this is on a test and I'm not allowed the cheat sheet?

17. anonymous

This one seems fairly easy now I know this forms a 60 30 90 triangle but what about something more irregular or do these always form 30-60-90 or 45-45-90 triangles?

18. anonymous

@satellite73

19. anonymous

(The ones they ask me to solve without a calculator.)

20. anonymous

@satellite73