## anonymous 3 years ago How do you find the curl of function f(x,y)=1111+(x/1100)^2

1. anonymous

$curl f=\left[\begin{matrix}i & j & k \\ \frac{\partial }{\partial x}& \frac{\partial }{\partial y}& \frac{\partial }{\partial z}\\ f_{x} & f_{y}& f_{z}\end{matrix}\right]$

2. anonymous

in your case f looks like scalar field. So there is no curl

3. anonymous

is that fx , fy and fz in 3rd row are you sure? isn't it cifficient of i j and k?

4. anonymous

that's what fx , fy and fz are. They are the components of f

5. anonymous

f should be a vector, if you whant to find it's curl. So it so it should look somthing like this: $f(x,y)=f_{x} i +f_{y} j$

6. anonymous

Here f describes pressure vector field in 2 dimension

7. anonymous

When you make contour plot you can see, pressure increasing from higher to lower region

8. anonymous

DO you know how to write this equation as vector field? I am given only this equation

9. anonymous

as I said befor. This equation asigns a numerical (scalar) value to every point in xy plane. So there is no vector field. The only vector field asociated with this sclara field is the field of grad f. But the curl(grad f)=0 always. That's all there is about this.

10. anonymous

ok thnks