## SUROJ 2 years ago How do you find the curl of function f(x,y)=1111+(x/1100)^2

1. myko

$curl f=\left[\begin{matrix}i & j & k \\ \frac{\partial }{\partial x}& \frac{\partial }{\partial y}& \frac{\partial }{\partial z}\\ f_{x} & f_{y}& f_{z}\end{matrix}\right]$

2. myko

in your case f looks like scalar field. So there is no curl

3. SUROJ

is that fx , fy and fz in 3rd row are you sure? isn't it cifficient of i j and k?

4. myko

that's what fx , fy and fz are. They are the components of f

5. myko

f should be a vector, if you whant to find it's curl. So it so it should look somthing like this: $f(x,y)=f_{x} i +f_{y} j$

6. SUROJ

Here f describes pressure vector field in 2 dimension

7. SUROJ

When you make contour plot you can see, pressure increasing from higher to lower region

8. SUROJ

DO you know how to write this equation as vector field? I am given only this equation

9. myko

as I said befor. This equation asigns a numerical (scalar) value to every point in xy plane. So there is no vector field. The only vector field asociated with this sclara field is the field of grad f. But the curl(grad f)=0 always. That's all there is about this.

10. SUROJ

ok thnks