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SUROJ

  • 2 years ago

How do you find the curl of function f(x,y)=1111+(x/1100)^2

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  1. myko
    • 2 years ago
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    \[curl f=\left[\begin{matrix}i & j & k \\ \frac{\partial }{\partial x}& \frac{\partial }{\partial y}& \frac{\partial }{\partial z}\\ f_{x} & f_{y}& f_{z}\end{matrix}\right]\]

  2. myko
    • 2 years ago
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    in your case f looks like scalar field. So there is no curl

  3. SUROJ
    • 2 years ago
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    is that fx , fy and fz in 3rd row are you sure? isn't it cifficient of i j and k?

  4. myko
    • 2 years ago
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    that's what fx , fy and fz are. They are the components of f

  5. myko
    • 2 years ago
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    f should be a vector, if you whant to find it's curl. So it so it should look somthing like this: \[f(x,y)=f_{x} i +f_{y} j\]

  6. SUROJ
    • 2 years ago
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    Here f describes pressure vector field in 2 dimension

  7. SUROJ
    • 2 years ago
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    When you make contour plot you can see, pressure increasing from higher to lower region

  8. SUROJ
    • 2 years ago
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    DO you know how to write this equation as vector field? I am given only this equation

  9. myko
    • 2 years ago
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    as I said befor. This equation asigns a numerical (scalar) value to every point in xy plane. So there is no vector field. The only vector field asociated with this sclara field is the field of grad f. But the curl(grad f)=0 always. That's all there is about this.

  10. SUROJ
    • 2 years ago
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    ok thnks

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