A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Given \(\vec{g} = 3\vec{i} + 6\vec{j}  12\vec{k}\) and \(\vec{h} = 5\vec{i}  10\vec{j} + 20\vec{k}\), how could I prove that \(\vec{g}\) and \(\vec{h}\) are parallel? Please explain the reasoning.
anonymous
 3 years ago
Given \(\vec{g} = 3\vec{i} + 6\vec{j}  12\vec{k}\) and \(\vec{h} = 5\vec{i}  10\vec{j} + 20\vec{k}\), how could I prove that \(\vec{g}\) and \(\vec{h}\) are parallel? Please explain the reasoning.

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0take their vector product, or prove they are multiple of each other

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well does a vector product of 0 allow me to conclude that they are parallel?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0g x h=ghsin(theta) where theta is angle between them. It will be = 0 only if angle is 0º or 180º

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok, just clarifying, is it because using the formal definition of the magnitude of a vector product, if \(\theta\) = 0º or 180º, it would cause the entire thing to become 0, and therefore parallel since an angle of 0º or 180º would be the same line or parallel?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, never mind, thank you!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0more easy: 5/3(3i+6j12h)=5i10j+20k

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ok. that is the reason the book gave me, so I'm curious as to why that works...I don't see where 5/3 comes from.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to make 3 equal to 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh. so you're multiplying \(\vec{g}\) by 5/3 to make it equal \(\vec{h}\)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, once again, thank you :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.