Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Hollywood_chrissy

Can somebody please explain th3 attached to me. is there a proof or something???

  • one year ago
  • one year ago

  • This Question is Closed
  1. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
  2. koalamon
    Best Response
    You've already chosen the best response.
    Medals 0

    just think about it, it will come to you.

    • one year ago
  3. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    @koalamon now about a hint

    • one year ago
  4. asnaseer
    Best Response
    You've already chosen the best response.
    Medals 0

    hint: in this equation:\[\frac{a+b}{a-b}=\frac{c+d}{c-d}\]divide the numerator and denominator of the left-hand-side by 'b' and divide the numerator and denominator of the right-hand-side by 'd'.

    • one year ago
  5. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    @asnaseer, even after your hint, i am still running into difficulty

    • one year ago
  6. DLS
    Best Response
    You've already chosen the best response.
    Medals 1

    Isn't this Componendo & Dividendo? ;)

    • one year ago
  7. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    what is componedo and dividendo???

    • one year ago
  8. DLS
    Best Response
    You've already chosen the best response.
    Medals 1

    It is a theorem in which the denominator is added to the numerator & numerator is added with negative denominator e. g. if \[\frac{x}{y}=\frac{a}{b}\] then by componendo & dividendo we have \[\frac{( x + y)}{( x- y ) }\]= \[\frac{( a +b )}{( a - b )}\] (Proof) \[\frac{3}{2}\] =\[\frac{ 6}{4}\] then by componendo & dividendo \[\frac{3+ 2}{3-2}\] = \[\frac{6 +4}{6- 4}\] OR 5/ 1 = 10/ 2 that is true

    • one year ago
  9. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    @DLS do you understand asnaseer's hint???

    • one year ago
  10. DLS
    Best Response
    You've already chosen the best response.
    Medals 1

    I think the theorem is better, he just said if u do the same thing/operation with a digit on one side,u do that on other too so overall effect nullifies

    • one year ago
  11. Hollywood_chrissy
    Best Response
    You've already chosen the best response.
    Medals 0

    you helped me greatly thanks

    • one year ago
  12. asnaseer
    Best Response
    You've already chosen the best response.
    Medals 0

    This is what I meant - starting with this:\[\frac{a+b}{a-b}=\frac{c+d}{c-d}\]lets first divide the numerator and denominator of the left-hand-side by 'b' to give:\[\frac{\frac{a}{b}+1}{\frac{a}{b}-1}=\frac{c+d}{c-d}\]then lets divide the numerator and denominator of the right-hand-side by 'd' to give:\[\frac{\frac{a}{b}+1}{\frac{a}{b}-1}=\frac{\frac{c}{d}+1}{\frac{c}{d}-1}\]now note that you are given that:\[\frac{a}{b}=\frac{c}{d}\]so the equality of both sides follows from this relation.

    • one year ago
  13. asnaseer
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't think you can just assume the "Componendo and dividendo" theorem directly as this question is effectively asking you to prove it.

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.