## anonymous 3 years ago How to find the Maclaurin series for f(x) using definition of a Maclaurin series: f(x) = ln(1+x)

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1. anonymous

$f'(x)=\frac{1}{1+x},f'(0)=\frac{1}{1}=1$$f''(x)=\frac{-1}{(1+x)^2},f''(0)=\frac{-1}{1^2}=-1$$f'''(x)=\frac{2}{(1+x)^3},f''(0)=\frac{2}{1^3}=2$

2. anonymous

Generally, for n>1, $f^n(0)=(-1)^{n-1}(n-1)!$

3. anonymous

Now just use the definition of Maclaurin: http://mathworld.wolfram.com/MaclaurinSeries.html Specifically, http://mathworld.wolfram.com/images/equations/MaclaurinSeries/NumberedEquation1.gif

4. anonymous

Any problem?