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DarkendSinz30

  • 2 years ago

I need help with this question Anyone please....

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  1. DarkendSinz30
    • 2 years ago
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    Assume that the population of heights of male college students is approximately normally distributed with mean  of 72.15 inches and standard deviation  of 6.39 inches. A random sample of 96 heights is obtained. Show all work. (A) Find P(x>73.25) (B) Find the mean and standard error of the xˉ distribution (C) Find P(xˉ > 73.25) (D) Why is the formula required to solve (A) different than (C)?

  2. jim_thompson5910
    • 2 years ago
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    for A and C, you need a calculator or a table

  3. jim_thompson5910
    • 2 years ago
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    for part b), the mean is xbar = 72.15 (since the mean of the xbar distribution is the population mean) and the standard error is sigma/sqrt(n) = 6.39/sqrt(96) = 0.6521766

  4. jim_thompson5910
    • 2 years ago
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    in part D, the difference between the two formulas comes from the fact that the standard deviations are different (in the population, it's 6.39, but in the xbar distribution, it's 0.6521766)

  5. DarkendSinz30
    • 2 years ago
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    okay thanks I see what your saying now

  6. jim_thompson5910
    • 2 years ago
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    np

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