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Kevin can jog to work in 7/12 of an hour. When he rides his bike, it takes him 1/6 of an hour. If he rides 12 miles per hour faster than he jogs, how far away is his work?
 one year ago
 one year ago
Kevin can jog to work in 7/12 of an hour. When he rides his bike, it takes him 1/6 of an hour. If he rides 12 miles per hour faster than he jogs, how far away is his work?
 one year ago
 one year ago

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geoffbBest ResponseYou've already chosen the best response.2
It's the same idea as before. The distance to work doesn't change.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Remember the formula \(d = vt\).
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Since \(d\) is the same no matter how he gets there, \((vt)_{jog} = (vt)_{bike}\).
 one year ago

zelloBest ResponseYou've already chosen the best response.0
but I don't know why in sometimes it becomes d1+d2
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
All I can think for that would be \(d_{1} + d_{2} = d_{total}\)
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
But that formula wouldn't apply for this question.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
\[vt 1=vt2\] \[\frac{ 1 }{ 7 }t=\frac{ 1 }{ 6 } (12t) \]
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Once you've determined what to equate (in this case, \(d\)), it's best to write out everything you need and see what you already know. That way, you know what to solve for. You're looking for \((vt)_{jog} = (vt)_{bike}\). There are 4 variables there: \[\begin{align*} v_{jog} &= \\ v_{bike} &= \\t_{jog} &= \\t_{bike} &= \end{align*}\]
 one year ago

zelloBest ResponseYou've already chosen the best response.0
So V for both will be 12 ?
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
You've used \(12  t\), which is not correct because the 12 relates to his velocity, not time. Go back to your question and see what you can plug in. You should end up with three answers (one will be relative), leaving one variable to solve for.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
No, V cannot be 12 for both.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
Okay so v bike = 12 and v jop= 12t
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
He doesn't bike at a velocity of 12.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
he rides 12 miles per hour faster than he jogs
 one year ago

zelloBest ResponseYou've already chosen the best response.0
He will ride a bike 12 miles per hour and he will jog 12t
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Nope. That's the same thing you said before. he does not bike at a speed of 12 mph. He bikes 12 mph *faster* than he jogs. You need to know how fast he jogs to know how fast he bikes.
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
" rides 12 miles per hour FASTER THAN" he jogs
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Have you plugged in your values for these? \[\begin{align*} v_{jog} &= \\ v_{bike} &= \\t_{jog} &= \\t_{bike} &= \end{align*}\]
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
If he bikes 12 mph faster than he jogs, \(v_{bike} = v_{jog} + 12\), right?
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
That should get you started. There are two more values you can plug in.
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
@zello then you'd better fill it in, keep in mind the unit match with variable !
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Yes! Keeping track of units is crucial, as is remembering what your variable means when you're done.
 one year ago

Bronco101Best ResponseYou've already chosen the best response.0
all i can get is he jogs for 35 minutes, and rides for 10 minutes. He rides 2 miles faster per 10 minutes than he jogs O.O
 one year ago

zelloBest ResponseYou've already chosen the best response.0
V bike= V jog+12 V jog = V bike12 T jog =7/12 T bike = 1/6
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Your times are right, but not your velocities.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
It's just Vjog. Don't equate it to anything. It will be the variable you solve for.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
\[vt Bike = vt Jog\] \[\frac{ 1 }{ 6 }(vJog+12) =\frac{ 7 }{ 12 } v\]
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Now solve for \(v_{jog}.\)
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
And remember—the v on the right side is also \(v_{jog}\).
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Call it \(v\), or \(x\), or whatever you want. It's the same no matter how you approach it. If the subscript "jog" confuses you, omit it, but remember what \(v\) represents.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{ 6 }(v+12)=\frac{ 7 }{ 12 }v\] \[\frac{ 1 }{ 6 }v+2=\frac{ 7 }{ 12 }\] \[\frac{ 1 }{ 6}v\frac{ 7 }{ 12 }v=2\] \[0.16v0.58=2\] \[0.42 v=2\] \[v=4.76\]
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
I left my answers in fractions, so I'm not sure. What do you get for your final answer?
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
@zello something isn't right with your calculation !
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
No, that's not what the question wants. Go back and read the last sentence.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
@Chlorophyll It's just rounding error. I got \(v_{jog} = \frac{24}{5}\), so I think he's okay.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Although I only looked at his answer, not his work.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Oh, I'm sorry. I judge too quickly by avatars.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Although that's obviously not you... :S
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Yes, it's very neat V = 24/5 ( 4.8 mi/hr) @zello Better keep it in fraction form!
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
@zello When you get to this stage: \[\frac{ 1 }{ 6}v\frac{ 7 }{ 12 }v=2\] Multiply everything by 12 and simplify to get rid of the fractions.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
I have a headache because from 9 A.M until now, I still working on my math >.<
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Well, you've been working hard, and definitely showing growth. You're welcome to take a break, but you're almost done this question. Remember, we needed to find \(v_{jog}\) to solve the equation, but \(v_{jog}\) is not what the question asks for. It asks how far away his work is.
 one year ago

zelloBest ResponseYou've already chosen the best response.0
how can i found the distance then
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
You know your distance formula. We've used it a lot.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
No, just \(d = vt\). You know \(v\) now, and you already knew \(t\), so solve for \(d\).
 one year ago

zelloBest ResponseYou've already chosen the best response.0
d bike = v bike * t bike d= 4.76 * 0.58 d= 2.7608
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Good. Don't forget your units. It's technically 2.8, so you're a bit off due to rounding errors, but that's right.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Excellent job working through this.
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
@zello I wonder if you know how to say thanks by distributing the medal (?)
 one year ago

zelloBest ResponseYou've already chosen the best response.0
Thank you so much and I'm sorry that I took a lot of your time. I really appreciate that
 one year ago

HeroBest ResponseYou've already chosen the best response.0
I got 2.8 exactly with my methods.
 one year ago

geoffbBest ResponseYou've already chosen the best response.2
Not a problem at all. Glad I could help. Thank you for making the effort to solve it on your own and learn.
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
Yup, that's why I say zello's calculation is incorrect!
 one year ago

zelloBest ResponseYou've already chosen the best response.0
It' not incorrect, it's just because I didn't round my answer
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
It's exact, so there's no need to round!
 one year ago

zelloBest ResponseYou've already chosen the best response.0
it's not exact in my calculator
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
So you're unable to calculate the fraction?
 one year ago

zelloBest ResponseYou've already chosen the best response.0
I know how to calculate the fraction but the question says that they want the answer rounded to the nearest tenth
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
First, you should keep the number in fraction if it isn't exact result Second, in this case it's exact! 7v / 12 = ( v + 12 ) /6 (7/ 12  1/6)v = 2 > v = 2 * 12/5 = 24/5 = 2.8 mi/ hr
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.1
There's nothing to round off :)
 one year ago

zelloBest ResponseYou've already chosen the best response.0
when I calculate it, I didn't use the fraction
 one year ago
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