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Mathhelp346

  • 3 years ago

PLEASE HELP PLEASE: Write each quadratic function in vertex form. Give the coordinates of the vertex and the equation of the axis of symmetry. Then describe the transformations from f(x)= x^2 to g. g(x)=-x^2+2

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  1. mark_o.
    • 3 years ago
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    do you know how to graph these two equation?

  2. Mathhelp346
    • 3 years ago
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    no

  3. mark_o.
    • 3 years ago
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    http://www.mathsisfun.com/data/function-grapher.php#functions

  4. mark_o.
    • 3 years ago
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    try that

  5. mark_o.
    • 3 years ago
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    can you see the vertex of each eq?

  6. Mathhelp346
    • 3 years ago
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    ..how do i enter them in?

  7. Mathhelp346
    • 3 years ago
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    nevermind

  8. Mathhelp346
    • 3 years ago
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    yes

  9. mark_o.
    • 3 years ago
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    now that you know the vertex of each you can write the vertex form of each of the equation

  10. mark_o.
    • 3 years ago
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    the vertex form formula is a(x-h)+k=0, where vertex= (h,k)

  11. Mathhelp346
    • 3 years ago
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    oh ok

  12. Mathhelp346
    • 3 years ago
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    so h is x and k is y

  13. mark_o.
    • 3 years ago
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    from ax^2 +bx +c=0 f(x)=-x^2+2= x^2 where b=0, c=0 g(x)=-x^2+2, where b=0,c=2

  14. Mathhelp346
    • 3 years ago
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    wait why is f(x)=-x^2+2= x^2? shouldn't it be just f(x)=x^2?

  15. mark_o.
    • 3 years ago
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    these two eQ are different, see the graph

  16. Mathhelp346
    • 3 years ago
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    why is the f(x) different?

  17. mark_o.
    • 3 years ago
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    the main form is f(x)=x^2 but if you change them to y=-x^2 now theres a negative sign then if you add 2 then you have to jump up 2 on y axis

  18. mark_o.
    • 3 years ago
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    did you see the difference between the two graph now?

  19. Mathhelp346
    • 3 years ago
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    oh so your showing the transformation?

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