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MarcLeclair

Use l'hopsital RUle to solve for lim x-->Pi / 4 5(1-tanx)secx. I solve for the equation (by plugging in pi/4) and I don't get zero, however, my answer is still wrong, should I still use the hospital rule?

  • one year ago
  • one year ago

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  1. tkhunny
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    \(\tan\left(\dfrac{\pi}{4}\right) = 1\) \(\sec\left(\dfrac{\pi}{4}\right) = \sqrt{2}\) 1) Never "plug in". Sometimes substitution is approprate. 2) This is not an indeterminate form. Please don't use l'Hopital's Rule. 3) Please supply the ENTIRE problem statement.

    • one year ago
  2. MarcLeclair
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    That is the entire problem. and I should've calculated in radian... right?

    • one year ago
  3. tkhunny
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    You can calculate in Light Years if you like. It's NOT an indeterminate form.

    • one year ago
  4. tkhunny
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    That doesn't mean we can't find the limit. We just can't use (or don't need) l'Hopital's Rule.

    • one year ago
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