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MarcLeclair
 3 years ago
Use l'hopsital RUle to solve for
lim x>Pi / 4 5(1tanx)secx.
I solve for the equation (by plugging in pi/4) and I don't get zero, however, my answer is still wrong, should I still use the hospital rule?
MarcLeclair
 3 years ago
Use l'hopsital RUle to solve for lim x>Pi / 4 5(1tanx)secx. I solve for the equation (by plugging in pi/4) and I don't get zero, however, my answer is still wrong, should I still use the hospital rule?

This Question is Closed

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1\(\tan\left(\dfrac{\pi}{4}\right) = 1\) \(\sec\left(\dfrac{\pi}{4}\right) = \sqrt{2}\) 1) Never "plug in". Sometimes substitution is approprate. 2) This is not an indeterminate form. Please don't use l'Hopital's Rule. 3) Please supply the ENTIRE problem statement.

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0That is the entire problem. and I should've calculated in radian... right?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1You can calculate in Light Years if you like. It's NOT an indeterminate form.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1That doesn't mean we can't find the limit. We just can't use (or don't need) l'Hopital's Rule.
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