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1/2 / (Square root of 3)/2

Mathematics
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Like this? \[\Large \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\]
Yeah!
Okay... \[\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}\]

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Other answers:

I keep getting the answer 1/squr root 3
and its supposed to be 3/ sqr root 3
So you can re-write it as: \[\frac{1}{2} \div \frac{\sqrt{3}}{2}\] which equals \[\frac{1}{2} \times \frac{2}{\sqrt{3}}\]
1/sqrt 3 would be correct, except you have to get rid of the squareroot in the denominator.
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Why cant it be in the denominator?
The answer is not \(\Large \frac{3}{\sqrt{3}}\).
Oops squr root 3/3 right?
There's nothing wrong with leaving it as \(\Large \frac{1}{\sqrt{3}}\), although if you understand negative exponents, there's a neater way you could write it.
Is it \[\frac{ \sqrt{3} }{ 3 }\]?
No. You were right with your answer. I was responding to your post that the answer is "supposed to be" 3/sqrt 3.
How though
It's not. You're right with 1/sqrt 3.
You're the one that said it's "supposed to be."
|dw:1354415644279:dw|
how is square root of 3 the square root of 3 =3? i thought it is 1
\[\sqrt{3} \times \sqrt{3} = 3\] I think he was trying to show how you could get the answer \( \Large \frac{\sqrt{3}}{3}\).
|dw:1354415812944:dw|
He's showing how to get rid of the radical. \(\Large \frac{1}{\sqrt{3}}\) is the same as \(\Large \frac{\sqrt{3}}{3}\).
ok thanks!

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