anonymous
  • anonymous
1/2 / (Square root of 3)/2
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Like this? \[\Large \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\]
anonymous
  • anonymous
Yeah!
anonymous
  • anonymous
Okay... \[\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}\]

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anonymous
  • anonymous
I keep getting the answer 1/squr root 3
anonymous
  • anonymous
and its supposed to be 3/ sqr root 3
anonymous
  • anonymous
So you can re-write it as: \[\frac{1}{2} \div \frac{\sqrt{3}}{2}\] which equals \[\frac{1}{2} \times \frac{2}{\sqrt{3}}\]
anonymous
  • anonymous
1/sqrt 3 would be correct, except you have to get rid of the squareroot in the denominator.
anonymous
  • anonymous
|dw:1354415263802:dw|
anonymous
  • anonymous
Why cant it be in the denominator?
anonymous
  • anonymous
The answer is not \(\Large \frac{3}{\sqrt{3}}\).
anonymous
  • anonymous
Oops squr root 3/3 right?
anonymous
  • anonymous
There's nothing wrong with leaving it as \(\Large \frac{1}{\sqrt{3}}\), although if you understand negative exponents, there's a neater way you could write it.
anonymous
  • anonymous
Is it \[\frac{ \sqrt{3} }{ 3 }\]?
anonymous
  • anonymous
No. You were right with your answer. I was responding to your post that the answer is "supposed to be" 3/sqrt 3.
anonymous
  • anonymous
How though
anonymous
  • anonymous
It's not. You're right with 1/sqrt 3.
anonymous
  • anonymous
You're the one that said it's "supposed to be."
anonymous
  • anonymous
|dw:1354415644279:dw|
anonymous
  • anonymous
how is square root of 3 the square root of 3 =3? i thought it is 1
anonymous
  • anonymous
\[\sqrt{3} \times \sqrt{3} = 3\] I think he was trying to show how you could get the answer \( \Large \frac{\sqrt{3}}{3}\).
anonymous
  • anonymous
|dw:1354415812944:dw|
anonymous
  • anonymous
He's showing how to get rid of the radical. \(\Large \frac{1}{\sqrt{3}}\) is the same as \(\Large \frac{\sqrt{3}}{3}\).
anonymous
  • anonymous
ok thanks!

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