smagyar
1/2 / (Square root of 3)/2
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geoffb
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Like this?
\[\Large \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\]
smagyar
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Yeah!
geoffb
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Okay...
\[\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}\]
smagyar
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I keep getting the answer 1/squr root 3
smagyar
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and its supposed to be 3/ sqr root 3
geoffb
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So you can re-write it as:
\[\frac{1}{2} \div \frac{\sqrt{3}}{2}\]
which equals
\[\frac{1}{2} \times \frac{2}{\sqrt{3}}\]
zordoloom
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1/sqrt 3 would be correct, except you have to get rid of the squareroot in the denominator.
smagyar
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|dw:1354415263802:dw|
smagyar
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Why cant it be in the denominator?
geoffb
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The answer is not \(\Large \frac{3}{\sqrt{3}}\).
smagyar
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Oops squr root 3/3 right?
geoffb
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There's nothing wrong with leaving it as \(\Large \frac{1}{\sqrt{3}}\), although if you understand negative exponents, there's a neater way you could write it.
smagyar
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Is it \[\frac{ \sqrt{3} }{ 3 }\]?
geoffb
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No. You were right with your answer. I was responding to your post that the answer is "supposed to be" 3/sqrt 3.
smagyar
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How though
geoffb
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It's not. You're right with 1/sqrt 3.
geoffb
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You're the one that said it's "supposed to be."
winterfez
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|dw:1354415644279:dw|
smagyar
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how is square root of 3 the square root of 3 =3? i thought it is 1
geoffb
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\[\sqrt{3} \times \sqrt{3} = 3\]
I think he was trying to show how you could get the answer \( \Large \frac{\sqrt{3}}{3}\).
winterfez
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|dw:1354415812944:dw|
geoffb
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He's showing how to get rid of the radical. \(\Large \frac{1}{\sqrt{3}}\) is the same as \(\Large \frac{\sqrt{3}}{3}\).
smagyar
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ok thanks!