## alyssababy7 2 years ago Use Cramer's rule to solve the system. 2x + 4y - z = 32 x - 2y + 2z = -5 5x + y + z = 20 A. {( 1, -9, -6)} B. {( 2, 7, 6)} C. {( 9, 6, 9)} D. {( 1, 9, 6)}

1. brandonloves

we can start by clearing the z on the first two for starters. we do that by multiplying 2 to the first problem which makes it 4x+8y-2z=44 and then add it to the second

2. brandonloves

I got 5x+6y=39

3. brandonloves

then multiply the last one times -2 so the z's will cancel

4. tkhunny

Cramer's Rule? Well, I suppose we could simplify it a little, first, but that is a little unusual. You have four 3x3 determinates in your future.

5. brandonloves

or you could do it that way. both take about as long to me...

6. tkhunny

I see, so we're just ignoring problem statements. :-(

7. Callisto

2x + 4y - z = 32 x - 2y + 2z = -5 5x + y + z = 20 $\Delta = \left| \begin{matrix}2 & 4 &-1\\ 1 & -2 & 2 \\ 5 &1 & 1\end{matrix}\right|=...$ $\Delta _{x} = \left| \begin{matrix}32 & 4 &-1\\ -5 & -2 & 2 \\ 20 &1 & 1\end{matrix}\right|=...$ $\Delta _{y} = \left| \begin{matrix}2 & 32 &-1\\ 1 & -5 & 2 \\ 5 & 20 & 1\end{matrix}\right|=...$ $\Delta _{z}= \left| \begin{matrix}2 & 4 & 32\\ 1 & -2 & -5 \\ 5 &1 & 20\end{matrix}\right|=...$ $x =\frac{\Delta _{x}}{\Delta}$$y =\frac{\Delta _{y}}{\Delta}$$z =\frac{\Delta _{z}}{\Delta}$ Haven't used Cramer's Rule for long :(