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alyssababy7
Group Title
Use Cramer's rule to solve the system. 2x + 4y  z = 32 x  2y + 2z = 5 5x + y + z = 20
A. {( 1, 9, 6)}
B. {( 2, 7, 6)}
C. {( 9, 6, 9)}
D. {( 1, 9, 6)}
 one year ago
 one year ago
alyssababy7 Group Title
Use Cramer's rule to solve the system. 2x + 4y  z = 32 x  2y + 2z = 5 5x + y + z = 20 A. {( 1, 9, 6)} B. {( 2, 7, 6)} C. {( 9, 6, 9)} D. {( 1, 9, 6)}
 one year ago
 one year ago

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brandonloves Group TitleBest ResponseYou've already chosen the best response.0
we can start by clearing the z on the first two for starters. we do that by multiplying 2 to the first problem which makes it 4x+8y2z=44 and then add it to the second
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
I got 5x+6y=39
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
then multiply the last one times 2 so the z's will cancel
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
Cramer's Rule? Well, I suppose we could simplify it a little, first, but that is a little unusual. You have four 3x3 determinates in your future.
 one year ago

brandonloves Group TitleBest ResponseYou've already chosen the best response.0
or you could do it that way. both take about as long to me...
 one year ago

tkhunny Group TitleBest ResponseYou've already chosen the best response.0
I see, so we're just ignoring problem statements. :(
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.0
2x + 4y  z = 32 x  2y + 2z = 5 5x + y + z = 20 \[\Delta = \left \begin{matrix}2 & 4 &1\\ 1 & 2 & 2 \\ 5 &1 & 1\end{matrix}\right=...\] \[\Delta _{x} = \left \begin{matrix}32 & 4 &1\\ 5 & 2 & 2 \\ 20 &1 & 1\end{matrix}\right=...\] \[\Delta _{y} = \left \begin{matrix}2 & 32 &1\\ 1 & 5 & 2 \\ 5 & 20 & 1\end{matrix}\right=...\] \[\Delta _{z}= \left \begin{matrix}2 & 4 & 32\\ 1 & 2 & 5 \\ 5 &1 & 20\end{matrix}\right=...\] \[x =\frac{\Delta _{x}}{\Delta}\]\[y =\frac{\Delta _{y}}{\Delta}\]\[z =\frac{\Delta _{z}}{\Delta}\] Haven't used Cramer's Rule for long :(
 one year ago
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