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Ambition

  • 3 years ago

Find all solutions in the interval [0, 2π). 4 sin2 x - 4 sin x + 1 = 0

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  1. Callisto
    • 3 years ago
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    Do you mean\[4 sin^2 x - 4 sin x + 1 = 0\]?

  2. Ambition
    • 3 years ago
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    yes sorry

  3. Callisto
    • 3 years ago
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    Nope :) Treat sinx as a, you'll get 4a^2 - 4a +1 =0 Can you solve this equation?

  4. Ambition
    • 3 years ago
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    not really

  5. Callisto
    • 3 years ago
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    Can you factorize the left side?

  6. Ambition
    • 3 years ago
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    no

  7. Callisto
    • 3 years ago
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    Hint: use \(a^2 -2ab +b^2 = (a-b)^2\)

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