anonymous
  • anonymous
why for dot multiplication in vectors gets abcos teeta,why not absinteeta ?
Physics
katieb
  • katieb
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anonymous
  • anonymous
!?!? what?!?!?!?!
anonymous
  • anonymous
you're answering to yourself?
ghazi
  • ghazi
dot product is a scalar quantity therefore applying product of two vectors in same direction will give scalar quantity, which is cos component of one in the direction of other, and reverse is in sin theta because it gives vector product

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anonymous
  • anonymous
What that doesn't make any sense.. the real reason why there are two kinds of products of vectors is because in nature .. we have defined quantities such that in some two vectors when multiplied gives a scalar .. EG work = force times displacement.. since work has to be scalar.. we define scalar product.. at the same time.. torque is force times position vector.. has to be a vector.. hence we define vector product.. So the two kinds of products in vectors are actually defined cause we need them to explain the above examples.. !
ghazi
  • ghazi
try to understand not to manipulate things , read what i have written, first, now things are not vector or scalar in real life , secondly, you need to understand what does scalar and vector stands for , define use first not define objects by tools, show use of tools to define object , hope this time it will make sense to you, whatever you have written is magnification of rote learning not the visualization of concept behind it
anonymous
  • anonymous
vectors and scalars are obviously DEFINED by us.. to deal and work with physical quantities BETTER!! "dot product is a scalar quantity therefore applying product of two vectors in same direction will give scalar quantity" This statement makes no sense what so ever.. product of two vectors in same direction will give scalar?!??! what you mean to say is.. the scalar product is basically telling how much two vectors are parallel to each other.. and the vector product how much two vectors are perpendicular to each other!
ghazi
  • ghazi
no again i am sorry to say you didnt get what i wrote i tried to define mathematically why we take cos component in dot product , well keep up the good work by the way thanks :)
anonymous
  • anonymous
so you mean to say.. since dot product is to find how much parallel they are.. we need to take the cos component of a vector .. so that we get the parallel component of it :P
ghazi
  • ghazi
NO
ghazi
  • ghazi
i said we take cos component because lets say if you are applying force of 10N on a block at an angle of 30 degrees then to find work we need to take dot product of it because that gives a scalar quantity and we take direction of motion in the direction of net force which makes the sense that you need to take cos component of force with the direction of motion, well it was nice to discuss i am off to bed now i am sorry its too late here : ):D
anonymous
  • anonymous
however.. what i am saying is.. its done the other way around :P.. dot product was not defined first.. we first define what work is .. and then since work is scalar and its a product of two vectors.. we then define what is called as the DOT product .. !!
ghazi
  • ghazi
cool, good night :)
anonymous
  • anonymous
gn!! :)

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