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DLS Group Title

DE

  • one year ago
  • one year ago

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  1. DLS Group Title
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    \[xcosy+ycosx=\tan^{-1}x^{2}\]

    • one year ago
  2. DLS Group Title
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    this is how i did it

    • one year ago
  3. DLS Group Title
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    \[\frac{d(xcosy)}{dx} + \frac{d(ycosx)}{dx} = d(\tan^{-1} x^{2})\]

    • one year ago
  4. DLS Group Title
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    \[cosy-xsin \frac{dy}{dx} + \dfrac{(ycosx)}{dx} - ysinx=\frac{1}{1+x^{4}}\]

    • one year ago
  5. DLS Group Title
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    \[\frac{dy}{dx}(cosx-xsiny)=\frac{1}{1+x^{4}}-cosy+ysinx\]

    • one year ago
  6. DLS Group Title
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    \[\frac{dy}{dx}=\frac{1}{1+x^{4}(cosy-xsiny}) - \frac{cosy+ysinx}{cosx-xsiny}\]

    • one year ago
  7. DLS Group Title
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    2nd equation is wrong sorry

    • one year ago
  8. hartnn Group Title
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    \(\large \frac{dy}{dx}=\frac{1}{(1+x^{4})(cosy-xsiny)}- \frac{cosy-ysinx}{cosx-xsiny}\)

    • one year ago
  9. DLS Group Title
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    \[cosy-xsiny \frac{dy}{dx} +cosx \frac{dy}{dx}-ysinx=\frac{1}{1+x^{4}}\]

    • one year ago
  10. DLS Group Title
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    oh so mine is correct? :O

    • one year ago
  11. hartnn Group Title
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    what u wrote now is correct.

    • one year ago
  12. DLS Group Title
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    finalans is correct right

    • one year ago
  13. hartnn Group Title
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    u get this \(\large \frac{dy}{dx}=\frac{1}{(1+x^{4})(cosy-xsiny)}- \frac{cosy-ysinx}{cosx-xsiny}\)

    • one year ago
  14. hartnn Group Title
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    cos y - y sin x

    • one year ago
  15. DLS Group Title
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    i got that only

    • one year ago
  16. hartnn Group Title
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    u got cos y+ y sin x

    • one year ago
  17. DLS Group Title
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    ah minor mistakes :p

    • one year ago
  18. DLS Group Title
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    if u open ur bracket u wud still get -cosy+ysinx i guess

    • one year ago
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