Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

tanyasachdeva1 Group Title

if volume of sphere increases by 72.8% what happen to the surface area?

  • 2 years ago
  • 2 years ago

  • This Question is Open
  1. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    V = 4/3 pi r^3 . this is a calculus differential question>

    • 2 years ago
  2. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe not

    • 2 years ago
  3. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    i didnt get it mam

    • 2 years ago
  4. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok , an increase of 72.8% is 172.8% of the original volume. do you agree ?

    • 2 years ago
  5. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    just like a 100% increase is actually double the original amount (200% of original amount)

    • 2 years ago
  6. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yuppp

    • 2 years ago
  7. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok so New Volume = 1.728 * Old volume

    • 2 years ago
  8. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    let the old volume be 4/3 pi * r^3. New Volume = 1.728 * 4/3 pi * r^3

    • 2 years ago
  9. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    yup but wht abt its surface area ?

    • 2 years ago
  10. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    we didnt get to that. one step at a time

    • 2 years ago
  11. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    who is that a picture of?

    • 2 years ago
  12. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

    • 2 years ago
  13. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so ... New volume = 4/3 pi [(1.728)^(1/3) * r ]^3

    • 2 years ago
  14. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    see how i brought in the 1.728, by taking the cube root (and then cubing it )

    • 2 years ago
  15. perl Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    anybody know what a cluster point is ? please help

    • 2 years ago
  16. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ??

    • 2 years ago
  17. matricked Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    since volume is directly proportional to r^3 hence if new volume is (100%+72.8%)=1.728 times the old volume then new r =cube root of (1.728) times old radius hence new r=1.2 times old r as surface area is directly proportional to r^2 hence new surface area =(1.2)^2 times old surface area=1.44 times old surface area hence increase in surface area =.44 times=44% increase

    • 2 years ago
  18. SUROJ Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Volume and surface area both depends on radius........so, you need to understand and calculate what happens to radius when volume increase by that much

    • 2 years ago
  19. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you so much to all...

    • 2 years ago
  20. tanyasachdeva1 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    ??

    • 2 years ago
  21. matricked Group Title
    Best Response
    You've already chosen the best response.
    Medals 3

    welcome

    • 2 years ago
  22. kropot72 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    The volume of a sphere is proportional to the radius cubed: \[volume=\frac{4}{3}\pi r ^{3}\] The surface area of a sphere is proportional to the radius squared: \[Surface\ area=4\pi r ^{2}\] Let the original radius = 1 unit Then for the volume to increase by 72.8%, the cube of the radius must increase from 1unit cubed up to 1.728 units cubed. This means the radius has increased from 1 unit up to \[\sqrt[3]{1.726}=1.2\ units\] Since the surface area is proportional to the radius squared, the square of the radius will increase from 1 unit squared up to \[1.2^{2}=1.44\] Therefore the surface area has increased by \[\frac{1.44-1}{1}\times 100=44\%\]

    • 2 years ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.