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tanyasachdeva1
Group Title
if volume of sphere increases by 72.8% what happen to the surface area?
 one year ago
 one year ago
tanyasachdeva1 Group Title
if volume of sphere increases by 72.8% what happen to the surface area?
 one year ago
 one year ago

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perl Group TitleBest ResponseYou've already chosen the best response.0
V = 4/3 pi r^3 . this is a calculus differential question>
 one year ago

tanyasachdeva1 Group TitleBest ResponseYou've already chosen the best response.0
i didnt get it mam
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
ok , an increase of 72.8% is 172.8% of the original volume. do you agree ?
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
just like a 100% increase is actually double the original amount (200% of original amount)
 one year ago

tanyasachdeva1 Group TitleBest ResponseYou've already chosen the best response.0
yuppp
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
ok so New Volume = 1.728 * Old volume
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
let the old volume be 4/3 pi * r^3. New Volume = 1.728 * 4/3 pi * r^3
 one year ago

tanyasachdeva1 Group TitleBest ResponseYou've already chosen the best response.0
yup but wht abt its surface area ?
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
we didnt get to that. one step at a time
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
who is that a picture of?
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
so ... New volume = 4/3 pi [(1.728)^(1/3) * r ]^3
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
see how i brought in the 1.728, by taking the cube root (and then cubing it )
 one year ago

perl Group TitleBest ResponseYou've already chosen the best response.0
anybody know what a cluster point is ? please help
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.3
since volume is directly proportional to r^3 hence if new volume is (100%+72.8%)=1.728 times the old volume then new r =cube root of (1.728) times old radius hence new r=1.2 times old r as surface area is directly proportional to r^2 hence new surface area =(1.2)^2 times old surface area=1.44 times old surface area hence increase in surface area =.44 times=44% increase
 one year ago

SUROJ Group TitleBest ResponseYou've already chosen the best response.0
Volume and surface area both depends on radius........so, you need to understand and calculate what happens to radius when volume increase by that much
 one year ago

tanyasachdeva1 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much to all...
 one year ago

kropot72 Group TitleBest ResponseYou've already chosen the best response.0
The volume of a sphere is proportional to the radius cubed: \[volume=\frac{4}{3}\pi r ^{3}\] The surface area of a sphere is proportional to the radius squared: \[Surface\ area=4\pi r ^{2}\] Let the original radius = 1 unit Then for the volume to increase by 72.8%, the cube of the radius must increase from 1unit cubed up to 1.728 units cubed. This means the radius has increased from 1 unit up to \[\sqrt[3]{1.726}=1.2\ units\] Since the surface area is proportional to the radius squared, the square of the radius will increase from 1 unit squared up to \[1.2^{2}=1.44\] Therefore the surface area has increased by \[\frac{1.441}{1}\times 100=44\%\]
 one year ago
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