## Kagome_gurl8 2 years ago A manufacturer determines that the number of drills it can sell is given by the formula D=-3p^2+180p-280, where p is the price of the drills in dollars.

1. Kagome_gurl8

a. At what price will the manufacturer sell the maximum number of drills? b. What is the maximum number of drills that can be sold?

2. Chlorophyll

Max point happens at x = -b/2a

3. Chlorophyll

Here x is p!

4. Kagome_gurl8

Understood but i am still confused....

5. Kagome_gurl8

on this question.... i keep trying to get a. but it always turns out to be 84. here are the answer choices \$30; 2,420 drills \$90; 8,380 drills \$60; 280 drills \$32; 2,427 drills

6. Chlorophyll

What do you get with p = 180/ 6 = ...?

7. Kagome_gurl8

30

8. matricked

u can use differentiation to obtain the results on differentiating u have -6p+180=0 or p=30 at this value of p the above expression may be maximum or minimum to check u differentiate (the result once more) now it stands -6 thus at p=30 the second ordr differentiation is neagtive and hence at p=30, D is amximum in order to obtain the max value of D use p=30 in D hope rest u get it...

9. Kagome_gurl8

Okay i got \$30; 2,420 drills Is this correct for both questions?

10. Chlorophyll

Does it take you 16hrs to plug 30 into the equation ?

11. Kagome_gurl8

no, im sorry i fell asleep.