Here's the question you clicked on:
Kagome_gurl8
A manufacturer determines that the number of drills it can sell is given by the formula D=-3p^2+180p-280, where p is the price of the drills in dollars.
a. At what price will the manufacturer sell the maximum number of drills? b. What is the maximum number of drills that can be sold?
Max point happens at x = -b/2a
Understood but i am still confused....
on this question.... i keep trying to get a. but it always turns out to be 84. here are the answer choices $30; 2,420 drills $90; 8,380 drills $60; 280 drills $32; 2,427 drills
What do you get with p = 180/ 6 = ...?
u can use differentiation to obtain the results on differentiating u have -6p+180=0 or p=30 at this value of p the above expression may be maximum or minimum to check u differentiate (the result once more) now it stands -6 thus at p=30 the second ordr differentiation is neagtive and hence at p=30, D is amximum in order to obtain the max value of D use p=30 in D hope rest u get it...
Okay i got $30; 2,420 drills Is this correct for both questions?
Does it take you 16hrs to plug 30 into the equation ?
no, im sorry i fell asleep.