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yasmin95
 3 years ago
find the equation of the tangent to the parabola x^2=16y at the point (4,1)
yasmin95
 3 years ago
find the equation of the tangent to the parabola x^2=16y at the point (4,1)

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Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1Differentiate both sides with respect to x, what do you get?

yasmin95
 3 years ago
Best ResponseYou've already chosen the best response.0i got this so far, y=x^2/16 dy/dx=2x/16 = x/8 at (4,1) dy/dx =4/8 =1/2

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1Yup! So, slope of tangent = m = 1/2 Equation of tangent required is y y1 = m (x x1) (x1, y1) = (4,1) Can you do it now?

yasmin95
 3 years ago
Best ResponseYou've already chosen the best response.0yeah but i don't know hw i keep getting x2y+4

yasmin95
 3 years ago
Best ResponseYou've already chosen the best response.0the answer is x2y2=0

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1y 1 = (1/2) (x 4) Multiply both sides by 2 2 (y1) = x4 Can you continue??
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