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find the equation of the tangent to the parabola x^2=16y at the point (4,1)
 one year ago
 one year ago
find the equation of the tangent to the parabola x^2=16y at the point (4,1)
 one year ago
 one year ago

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CallistoBest ResponseYou've already chosen the best response.1
Differentiate both sides with respect to x, what do you get?
 one year ago

yasmin95Best ResponseYou've already chosen the best response.0
i got this so far, y=x^2/16 dy/dx=2x/16 = x/8 at (4,1) dy/dx =4/8 =1/2
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
Yup! So, slope of tangent = m = 1/2 Equation of tangent required is y y1 = m (x x1) (x1, y1) = (4,1) Can you do it now?
 one year ago

yasmin95Best ResponseYou've already chosen the best response.0
yeah but i don't know hw i keep getting x2y+4
 one year ago

yasmin95Best ResponseYou've already chosen the best response.0
the answer is x2y2=0
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
y 1 = (1/2) (x 4) Multiply both sides by 2 2 (y1) = x4 Can you continue??
 one year ago
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