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yasmin95

  • 2 years ago

find the equation of the tangent to the parabola x^2=16y at the point (4,1)

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  1. Callisto
    • 2 years ago
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    Differentiate both sides with respect to x, what do you get?

  2. yasmin95
    • 2 years ago
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    i got this so far, y=x^2/16 dy/dx=2x/16 = x/8 at (4,1) dy/dx =4/8 =1/2

  3. Callisto
    • 2 years ago
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    Yup! So, slope of tangent = m = 1/2 Equation of tangent required is y- y1 = m (x -x1) (x1, y1) = (4,1) Can you do it now?

  4. yasmin95
    • 2 years ago
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    yeah but i don't know hw i keep getting x-2y+4

  5. yasmin95
    • 2 years ago
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    the answer is x-2y-2=0

  6. Callisto
    • 2 years ago
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    y- 1 = (1/2) (x -4) Multiply both sides by 2 2 (y-1) = x-4 Can you continue??

  7. yasmin95
    • 2 years ago
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    yeah thanks !!

  8. Callisto
    • 2 years ago
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    Welcome :)

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