anonymous
  • anonymous
find the equation of the tangent to the parabola x^2=16y at the point (4,1)
Mathematics
jamiebookeater
  • jamiebookeater
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Callisto
  • Callisto
Differentiate both sides with respect to x, what do you get?
anonymous
  • anonymous
i got this so far, y=x^2/16 dy/dx=2x/16 = x/8 at (4,1) dy/dx =4/8 =1/2
Callisto
  • Callisto
Yup! So, slope of tangent = m = 1/2 Equation of tangent required is y- y1 = m (x -x1) (x1, y1) = (4,1) Can you do it now?

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anonymous
  • anonymous
yeah but i don't know hw i keep getting x-2y+4
anonymous
  • anonymous
the answer is x-2y-2=0
Callisto
  • Callisto
y- 1 = (1/2) (x -4) Multiply both sides by 2 2 (y-1) = x-4 Can you continue??
anonymous
  • anonymous
yeah thanks !!
Callisto
  • Callisto
Welcome :)

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