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yasmin95
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find the equation of the tangent to the parabola x^2=16y at the point (4,1)
 one year ago
 one year ago
yasmin95 Group Title
find the equation of the tangent to the parabola x^2=16y at the point (4,1)
 one year ago
 one year ago

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Callisto Group TitleBest ResponseYou've already chosen the best response.1
Differentiate both sides with respect to x, what do you get?
 one year ago

yasmin95 Group TitleBest ResponseYou've already chosen the best response.0
i got this so far, y=x^2/16 dy/dx=2x/16 = x/8 at (4,1) dy/dx =4/8 =1/2
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Yup! So, slope of tangent = m = 1/2 Equation of tangent required is y y1 = m (x x1) (x1, y1) = (4,1) Can you do it now?
 one year ago

yasmin95 Group TitleBest ResponseYou've already chosen the best response.0
yeah but i don't know hw i keep getting x2y+4
 one year ago

yasmin95 Group TitleBest ResponseYou've already chosen the best response.0
the answer is x2y2=0
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
y 1 = (1/2) (x 4) Multiply both sides by 2 2 (y1) = x4 Can you continue??
 one year ago

yasmin95 Group TitleBest ResponseYou've already chosen the best response.0
yeah thanks !!
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Welcome :)
 one year ago
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