## anonymous 4 years ago Prove 2^(1/4)*4^(1/8)*8^(1/16)*16^(1/32) ... ∞ = 2. Alternative view : http://www.wolframalpha.com/input/?i=2%5E%281%2F4%29*4%5E%281%2F8%29*8%5E%281%2F16%29*16%5E%281%2F32%29+...+%E2%88%9E+%3D+2&dataset=&equal=Submit

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1. anonymous

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2. anonymous

let's see what is its closed form $\large \prod_{n=1}^{\infty} (2^n)^{\frac{1}{2^{n+1}}}=\prod_{n=1}^{\infty} (2)^{\frac{n}{2^{n+1}}}=2^{\sum_{n=1}^{\infty} \frac{n}{2^{n+1}}}=2$so u just need to show that $\large \sum_{n=1}^{\infty} \frac{n}{2^{n+1}}=1$

3. anonymous

make sense ???