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jennilalala Group Title

Use the shell method to find the volume of the solid generated by revolving about the y-axis. x=sqrt(9-x^2) and x=0

  • one year ago
  • one year ago

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  1. Callisto Group Title
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    The equation should be\[y =\sqrt{9-x^2}\]?

    • one year ago
  2. Callisto Group Title
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    Assume the equation of the line is \(y=\sqrt{9-x^2}\) Domain of the function: [-3, 3] So, integrate from x=0 to x=3 \[V=\int_0^3 2\pi xf(x) dx = 2\pi \int_0^3 x\sqrt{9-x^2} dx=...\]

    • one year ago
  3. RadEn Group Title
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    if revolving about the y-axis, the integration should forward dy so, v=pi*int((f(y))^2 dy [y1,y2] with y1 and y2 are under interval and up interval respectively

    • one year ago
  4. Callisto Group Title
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    Shell method.... about y-axis => dx See this: http://mathworld.wolfram.com/MethodofShells.html

    • one year ago
  5. Callisto Group Title
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    @RadEn Yours is disc method, I think

    • one year ago
  6. RadEn Group Title
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    yea, sorry i knew just new about the sell methode, @Callisto... sorry again :)

    • one year ago
  7. Callisto Group Title
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    It's okay, don't worry :)

    • one year ago
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