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Use the shell
method to ﬁnd the volume of the solid generated by revolving
about the yaxis.
x=sqrt(9x^2) and x=0
 one year ago
 one year ago
Use the shell method to ﬁnd the volume of the solid generated by revolving about the yaxis. x=sqrt(9x^2) and x=0
 one year ago
 one year ago

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CallistoBest ResponseYou've already chosen the best response.2
The equation should be\[y =\sqrt{9x^2}\]?
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
Assume the equation of the line is \(y=\sqrt{9x^2}\) Domain of the function: [3, 3] So, integrate from x=0 to x=3 \[V=\int_0^3 2\pi xf(x) dx = 2\pi \int_0^3 x\sqrt{9x^2} dx=...\]
 one year ago

RadEnBest ResponseYou've already chosen the best response.0
if revolving about the yaxis, the integration should forward dy so, v=pi*int((f(y))^2 dy [y1,y2] with y1 and y2 are under interval and up interval respectively
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
Shell method.... about yaxis => dx See this: http://mathworld.wolfram.com/MethodofShells.html
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
@RadEn Yours is disc method, I think
 one year ago

RadEnBest ResponseYou've already chosen the best response.0
yea, sorry i knew just new about the sell methode, @Callisto... sorry again :)
 one year ago

CallistoBest ResponseYou've already chosen the best response.2
It's okay, don't worry :)
 one year ago
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