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anonymous
 3 years ago
Use the shell
method to ﬁnd the volume of the solid generated by revolving
about the yaxis.
x=sqrt(9x^2) and x=0
anonymous
 3 years ago
Use the shell method to ﬁnd the volume of the solid generated by revolving about the yaxis. x=sqrt(9x^2) and x=0

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Callisto
 3 years ago
Best ResponseYou've already chosen the best response.2The equation should be\[y =\sqrt{9x^2}\]?

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.2Assume the equation of the line is \(y=\sqrt{9x^2}\) Domain of the function: [3, 3] So, integrate from x=0 to x=3 \[V=\int_0^3 2\pi xf(x) dx = 2\pi \int_0^3 x\sqrt{9x^2} dx=...\]

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0if revolving about the yaxis, the integration should forward dy so, v=pi*int((f(y))^2 dy [y1,y2] with y1 and y2 are under interval and up interval respectively

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.2Shell method.... about yaxis => dx See this: http://mathworld.wolfram.com/MethodofShells.html

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.2@RadEn Yours is disc method, I think

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0yea, sorry i knew just new about the sell methode, @Callisto... sorry again :)

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.2It's okay, don't worry :)
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