Here's the question you clicked on:
thomas5267
Rewrite \(\int^3_2\frac{3x}{x^2-4x+5}\,dx\) into the form of \(\int^b_a\frac{mt+c}{t^2+k^2}\) or \(\int^b_a\frac{mt+c}{t^2-k^2}\). Completing the square, as far as I can see, wouldn't work this time. What should I do with this?
\[\int^3_2\frac{3x}{x^2-4x+5}dx=\int^3_2\frac{3x}{x^2-4x+(4+1)}dx=\int^3_2\frac{3x}{(x-2)^2+1}dx\]In this case, t=x-2, k=1
*facepalm* I am such an idiot.