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Rewrite \(\int^3_2\frac{3x}{x^24x+5}\,dx\) into the form of \(\int^b_a\frac{mt+c}{t^2+k^2}\) or \(\int^b_a\frac{mt+c}{t^2k^2}\).
Completing the square, as far as I can see, wouldn't work this time. What should I do with this?
 one year ago
 one year ago
Rewrite \(\int^3_2\frac{3x}{x^24x+5}\,dx\) into the form of \(\int^b_a\frac{mt+c}{t^2+k^2}\) or \(\int^b_a\frac{mt+c}{t^2k^2}\). Completing the square, as far as I can see, wouldn't work this time. What should I do with this?
 one year ago
 one year ago

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CallistoBest ResponseYou've already chosen the best response.1
\[\int^3_2\frac{3x}{x^24x+5}dx=\int^3_2\frac{3x}{x^24x+(4+1)}dx=\int^3_2\frac{3x}{(x2)^2+1}dx\]In this case, t=x2, k=1
 one year ago

thomas5267Best ResponseYou've already chosen the best response.0
*facepalm* I am such an idiot.
 one year ago
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