anonymous
  • anonymous
Solve the following system: 2^(x+3y) = 128 and 2^(3x–y) = 2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mayankdevnani
  • mayankdevnani
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hba
  • hba
Apply log.
Callisto
  • Callisto
128 = 2^7 So, 2^(x+3y) = 128 2^(x+3y) = 2^7 Since the bases on both sides are the same, you can equate the power x+3y = 7 <- This is equation 1 2^(3x–y) = 2 2^(3x–y) = 2^1 Since the bases on both sides are the same, you can equate the power 3x-y = 1 <- this is equation 2 You have two equations and two unknowns. You can solve them now.

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