A community for students.
Here's the question you clicked on:
 0 viewing
jmays14
 3 years ago
Horizontal asymptote of the function f(x)= 6x^3+17x^2528/2x^314x+321
jmays14
 3 years ago
Horizontal asymptote of the function f(x)= 6x^3+17x^2528/2x^314x+321

This Question is Closed

jmays14
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(x) = 6x^3+17x^2528/2x^314x+321\]

jmays14
 3 years ago
Best ResponseYou've already chosen the best response.0can someone help me please

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Horizontal asymptotes \[=f(x) = \lim_{x \rightarrow \infty} \frac{6x^3+17x^2528}{2x^314x+321}=...\]

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0Divide both the numerator and denominator by x^3

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0And \[\lim_{x \rightarrow \infty} \frac{1}{x} =0\]

jmays14
 3 years ago
Best ResponseYou've already chosen the best response.0what is the next step , i believe 3 is right

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow \infty} \frac{6x^3+17x^2528}{2x^314x+321}\]\[=\lim_{x \rightarrow \infty} \frac{\frac{6x^3+17x^2528}{x^3}}{\frac{2x^314x+321}{x^3}}\]\[=\lim_{x \rightarrow \infty} \frac{6+\frac{17}{x}\frac{528}{x^3}}{2\frac{14}{x^2}+\frac{321}{x^3}}\]Then take the limit
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.