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jmays14

Horizontal asymptote of the function f(x)= 6x^3+17x^2-528/2x^3-14x+321

  • one year ago
  • one year ago

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  1. jmays14
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    \[f(x) = 6x^3+17x^2-528/2x^3-14x+321\]

    • one year ago
  2. jmays14
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    can someone help me please

    • one year ago
  3. Callisto
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    Horizontal asymptotes \[=f(x) = \lim_{x \rightarrow \infty} \frac{6x^3+17x^2-528}{2x^3-14x+321}=...\]

    • one year ago
  4. jmays14
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    yes thats the problem

    • one year ago
  5. Callisto
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    Divide both the numerator and denominator by x^3

    • one year ago
  6. Callisto
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    And \[\lim_{x \rightarrow \infty} \frac{1}{x} =0\]

    • one year ago
  7. jmays14
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    i got 3

    • one year ago
  8. Callisto
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    Isn't it correct?!

    • one year ago
  9. jmays14
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    what is the next step , i believe 3 is right

    • one year ago
  10. Callisto
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    It is 3..

    • one year ago
  11. Callisto
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    \[\lim_{x \rightarrow \infty} \frac{6x^3+17x^2-528}{2x^3-14x+321}\]\[=\lim_{x \rightarrow \infty} \frac{\frac{6x^3+17x^2-528}{x^3}}{\frac{2x^3-14x+321}{x^3}}\]\[=\lim_{x \rightarrow \infty} \frac{6+\frac{17}{x}-\frac{528}{x^3}}{2-\frac{14}{x^2}+\frac{321}{x^3}}\]Then take the limit

    • one year ago
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