Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

IBstudent

  • 3 years ago

Quadratic equations: Solve for x: X4 - 5X2 + 4 = 0

  • This Question is Closed
  1. Yza
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In quadratic form, the equation would be -5x2 + x4 + 4 = 0

  2. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Wouldn´t this equation written in this way x^4-5x^2+4=0

  3. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ?

  4. Yza
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    But you would have to have the equation in ax^2 + bx + c form

  5. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    If this equation has the form above so try to factor out.

  6. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    -5x2 + x4 + 4 = 0. From here you can use (x^2-4)(x^2-1);

  7. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Reminder if ab=0 then a=0 or b=0

  8. zordoloom
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    X^4-5X^2+4=0 Substitute u=X^2 into the equation. This will make the quadratic formula easy to use. u^2-5u+4=0 u=X^2 Move -4 to the left-hand side of the equation by adding it to both sides. The goal is to have all terms on the left-hand side equal to 0. u^2-5u+4=0 In this problem -1*-4=4 and -1-4=-5, so insert -1 as the right hand term of one factor and -4 as the right-hand term of the other factor. (u-1)(u-4)=0 Set each of the factors of the left-hand side of the equation equal to 0. u-1=0 u-4=0 Since -1 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 1 to both sides. u=1 u-4=0 Set each of the factors of the left-hand side of the equation equal to 0. u=1 u-4=0 Since -4 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 4 to both sides. u=1 u=4 The complete solution is the set of the individual solutions. u=1, 4 Substitute the real value of u=X^2 back into the solved equation. X^2=1 X^2=4 Solve the first equation for X. X^2=1 Take the square root of both sides of the equation to eliminate the exponent on the left-hand side. X=+/-sqrt(1) Pull all perfect square roots out from under the radical. In this case, remove the 1 because it is a perfect square. X=+/-1 First, substitute in the + portion of the +/- to find the first solution. X=1 Next, substitute in the - portion of the +/- to find the second solution. X=-1 The complete solution is the result of both the + and - portions of the solution. X=1,-1 Solve the second equation for X. X^2=4 Take the square root of both sides of the equation to eliminate the exponent on the left-hand side. X=+/-sqrt(4) Pull all perfect squXre roots out from under the radical. In this case, remove the 2 because it is a perfect square. X=+/-2 First, substitute in the + portion of the +/- to find the first solution. X=2 Next, substitute in the - portion of the +/- to find the second solution. X=-2 The complete solution is the result of both the + and - portions of the solution. X=2,-2 The solution to X^4-5X^2+4=0 is X=1,-1,2,-2. X=1,-1,2,-2

  9. viniterranova
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Two different ways of solving but the same answer.

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy