A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Quadratic equations:
Solve for x:
X4  5X2 + 4 = 0
anonymous
 3 years ago
Quadratic equations: Solve for x: X4  5X2 + 4 = 0

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0In quadratic form, the equation would be 5x2 + x4 + 4 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wouldn´t this equation written in this way x^45x^2+4=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But you would have to have the equation in ax^2 + bx + c form

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If this equation has the form above so try to factor out.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05x2 + x4 + 4 = 0. From here you can use (x^24)(x^21);

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Reminder if ab=0 then a=0 or b=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0X^45X^2+4=0 Substitute u=X^2 into the equation. This will make the quadratic formula easy to use. u^25u+4=0 u=X^2 Move 4 to the lefthand side of the equation by adding it to both sides. The goal is to have all terms on the lefthand side equal to 0. u^25u+4=0 In this problem 1*4=4 and 14=5, so insert 1 as the right hand term of one factor and 4 as the righthand term of the other factor. (u1)(u4)=0 Set each of the factors of the lefthand side of the equation equal to 0. u1=0 u4=0 Since 1 does not contain the variable to solve for, move it to the righthand side of the equation by adding 1 to both sides. u=1 u4=0 Set each of the factors of the lefthand side of the equation equal to 0. u=1 u4=0 Since 4 does not contain the variable to solve for, move it to the righthand side of the equation by adding 4 to both sides. u=1 u=4 The complete solution is the set of the individual solutions. u=1, 4 Substitute the real value of u=X^2 back into the solved equation. X^2=1 X^2=4 Solve the first equation for X. X^2=1 Take the square root of both sides of the equation to eliminate the exponent on the lefthand side. X=+/sqrt(1) Pull all perfect square roots out from under the radical. In this case, remove the 1 because it is a perfect square. X=+/1 First, substitute in the + portion of the +/ to find the first solution. X=1 Next, substitute in the  portion of the +/ to find the second solution. X=1 The complete solution is the result of both the + and  portions of the solution. X=1,1 Solve the second equation for X. X^2=4 Take the square root of both sides of the equation to eliminate the exponent on the lefthand side. X=+/sqrt(4) Pull all perfect squXre roots out from under the radical. In this case, remove the 2 because it is a perfect square. X=+/2 First, substitute in the + portion of the +/ to find the first solution. X=2 Next, substitute in the  portion of the +/ to find the second solution. X=2 The complete solution is the result of both the + and  portions of the solution. X=2,2 The solution to X^45X^2+4=0 is X=1,1,2,2. X=1,1,2,2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Two different ways of solving but the same answer.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.