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I need the order to be as dxdy? and sketch the prism ? i guess the vol= pi*y^2

Oh yes the lengtth is 4cm sorry i missed that out!

let me skecth it...

|dw:1354460197419:dw|

Some thing like that for the first area?

so you can see why they call it a "prism"
so, where is the intersection point?

what is this point?|dw:1354461347743:dw|

1 to 0 -root2 to 0?

I mean lower to upper*

Sorry , 0 to 1, . 0 to 3+root2

im not sure as there are 2 seperate coordinates ?which do i sub in?

one double integral of course*

oh right so your dont have to compute the values of x=2,1 why is that?

here is the first integral|dw:1354462159166:dw|

|dw:1354462244107:dw|so going along x last, this is why we needed two integrals....

right i see so the values of x=1 , 2 are subed into (x-2)^2 to get 0 to1..

yes is can clearly see its from o to 1.. its much easir sketching it !

no, it sounds very wrong, read what I wrote: this is NOT A VOLUME OF REVOLUTION

whether 8/3 is the final answer or not depends on what the 4 represents in your initial problem

I finally get it lol the inregral is the area = 8/3 and the h=4cm so v=a*h v=32/3 cm^3

32/3?

no, reread please

2/3 divide it by 4

why divide?

yes, that is my whole point

I guess you really need to read the question Lol..!

and you're welcome :)

Yes is mean fourier series sorry.

okay, it's been a reeeeeeeally long time for me with Foiurier series, but I'll have a look.

you should really post the problem separately, as a new thread

A periodic funtion F(t) is defined by f(t)=t^2, over -pi

I don't think I know how to do this though...

For be its meant to be f(t) only not f(t0

it is fourier series not transform.