Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Kamille

  • 2 years ago

Hello, can someone help me? I have a reaction: 2Mg+O2->2MgO Also, I know that mass of Mg is 9g mass of O2 is 8g What is the mass of MgO?

  • This Question is Closed
  1. yrelhan4
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    find the moles f each mg and o2. check which is the limiting reagent. that many moles of mgo will be formed. also note x moles of mg will give x moles of mgo. but x moles of o2 will give 2x oles of mgo.

  2. justine97
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1. Find moles of Mg and O2 Mg → 9/24.3 = .37 mol Mg O2 → 8/16.0 = .50 mol O2 2. Find the limiting reactant (moles of each substance divided by coefficient) Mg → .37mol ÷ 2 mol = .19 O2 → .50 mol ÷ 1 mol = .5 Limiting reactant (smallest number) = Mg 3. Use moles of Mg to find how many moles of MgO formed \[\frac{ 2 mol Mg }{ 2 mol MgO } = \frac{ .5 mol O2 }{ x }\] x = .5 mol MgO formed 4. Convert moles of MgO to grams MgO → .5(24.3g) + .5(16.0g) = 20.15g Answer: 20.15 grams MgO

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.