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dddan
please help!! how do u solve for b^3+20b=9b^2?
rewrite the equation so that you have \[b^3 - 9b^2 + 20b = 0\] now take b as a common factor \[b(b^2 - 9b + 20) = 0\] factor the quadratic in the brackets... you need the factors of 20 than add to -9.... they are both negatives... then you should be able to find the solutions.
well you'll have \[b(b -5)(b-4) = 0\] so the solutions are b = 0, 4, 5