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campbell_st Group TitleBest ResponseYou've already chosen the best response.1
rewrite the equation so that you have \[b^3  9b^2 + 20b = 0\] now take b as a common factor \[b(b^2  9b + 20) = 0\] factor the quadratic in the brackets... you need the factors of 20 than add to 9.... they are both negatives... then you should be able to find the solutions.
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
so is it 5 and 4?
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
well you'll have \[b(b 5)(b4) = 0\] so the solutions are b = 0, 4, 5
 2 years ago
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