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campbell_st Group TitleBest ResponseYou've already chosen the best response.1
rewrite the equation so that you have \[b^3  9b^2 + 20b = 0\] now take b as a common factor \[b(b^2  9b + 20) = 0\] factor the quadratic in the brackets... you need the factors of 20 than add to 9.... they are both negatives... then you should be able to find the solutions.
 one year ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
so is it 5 and 4?
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
well you'll have \[b(b 5)(b4) = 0\] so the solutions are b = 0, 4, 5
 one year ago
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