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alexeis_nicole

  • 2 years ago

for each following values of cos θ, determine the radian value of θ if π≤θ≤2π. a) \[-\frac{ 1 }{ 2 }\] b) \[\frac{ \sqrt{3} }{ 2 }\] c) \[-\frac{ \sqrt{2} }{ 2 }\]

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  1. cwrw238
    • 2 years ago
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    hint : cos theta = 1/2 : radian value of theta in first quadrant is pi/3 for sqrt3/2 its pi/6 for sqrt2/2 over 2 its pi/4

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