Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Short Leg= 2x6
Long leg= 2x
Longest= 30
Find the missing sides to get 30
 one year ago
 one year ago
Short Leg= 2x6 Long leg= 2x Longest= 30 Find the missing sides to get 30
 one year ago
 one year ago

This Question is Closed

tkhunnyBest ResponseYou've already chosen the best response.1
Perhaps there was a figure or a description of a figure?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I can't screenshot the figure. The codes in the page prevent it.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
And you are entirely unable to describe it?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
its Pythagoreon Theorem
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
a squared plus b squared equals c squared
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Okay, then you should apply that. Can you identify a, b, and c?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Reread the question.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
You did what? Fill n the blanks... For the Pythagorean Theorem, I need to identify a, b, and c. a = ?? b = ?? c = 30
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
A equals short leg
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
B equals the other leg
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
C equals longest leg
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Okay. What did the Pythagorean Theorem look like when you substituted those values?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
When I squared them all?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Did you do that? Yes. What did you get?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I have not done it yet because that and the whole problem is where my confusion lies.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
I think we have established this: a = 2x6 b = 2x c = 30 We have also established the Pythagorean Theorem \(a^{2} + b^{2} = c^{2}\) Now our task is to substitute the given values into the Pythagorean Theorem. You do that and let's see if you wander off.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I wander off in the beginning.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Stop saying that and simply start writing. Change your screen name. Do SOMETHING so that you can win one battle, here. You seem to be in the wrong class. How can we move you toward a more positive outcome? I can't get you to write ANYTHING. That's not good.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I have Aspbergers. Either bear with my incompetence that I was born with or help me find someone who can help.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
You didn't answer my question. Can you substitute the known values into the known formula, or not? Do you know what substitution means? Have you ever seen the process?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Thank you for your help. Good day.
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
What tkhunny is asking is which is the hypothenuse and the adjacent side.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
What tk hunny was not understanding is I wrote them already and as neither side is in normal form I am confused.
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Would you be able to use the draw option under the chat log to drwa the picture for us?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
maybe im on a laptop
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Just do your best, if you have problem explaining it is much easier to see a picture. If we can't understand your question, we will not be able to help.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
dw:1354487589391:dw
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
okay tell me if im right:dw:1354487622965:dw
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
the one that are perpendicular?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
2x should be on the bottom with 2x minus 6 on the left the 30 is in the right spot
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
dw:1354487934867:dw
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
okay that helps, so you want to solve for x. Because you have 1 variable ( which in this case would be x, and I'm assuming you know what variable means) In this case you have a formula relating all angle. We will call it as follow ( because a square + b square = c sqare is too vague and can confuse you): Opposite + adjacent = hypothenuse. Now you're hypothenuse is a mathematical term for what you called " longest leg" which is mathematically wrong to say. Your opposite and adjacent is the two other "Legs" and is relative (therefore meaning it all depends on how you see it) to what you want. I relate the BOTTOM RIGHT angle always. THerefore my opposite side is the 2x6 and the adjacent is 2x Now come the equation which is as follow: adjacent(squared) + opposite(squared) = hypothenuse (squared) Plug in ( therefore replace the word corresponding to the right side) with the right equation, and solve for x Can you solve for x?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I get legs. I don't get math terms. Can you show me a visual?
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
dw:1354488141269:dw
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
yikes. Hum alright, ill try another way. When you solve for an equation, at your level, you have only one variable : x
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Ok stop just for a moment. You are going way too bloody complex. I don't get complex and I don't get abstract.
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Ah I'm sorry my friend then, I hope you find someone who can give you a better explanation
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I have Aspbergers I am used to not being able to find help really.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Why as Aspergers a restriction on your ability to visualize, follow abstraction, or communicate symbolically? It that the only diagnosis? You are so SURE that you CAN'T get it, and you know EXACTLY what it is you can't get, that I have to wonder if we don't have other pathologies at play, here. If you don't get abstract, complex, or math symbols, how do you know you have encountered such a thing?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Have you ever looked up Aspbergers? Researched it? Lived it?
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
By your replies I can say no you have not. Aspbergers is a Social Disorder in the DMV book and can affect the ability to comprehend abstract concepts in Math, English, Reading, Writing, and also affects Social Skills.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Yes, Yes, and Yes. But I had no cognitive difficulty related to mathematics. That's why I'm puzzled. It's quite a different presentation than I've previously encountered. I've only seen social aspects.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Not every Aspbergers person is the same.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Clearly. Are you aware of what level of abstration can you handle? You seemed to be okay calling a leg of a triangle '2x' and another leg '2x6'.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
It is obvious you can't help me. Good day.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Not if you don't talk to me and you just punt.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
New problem got it wrong :( let me write the new one
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
nvm same problem as this one lol
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
short leg = 2x  6 long leg = 2x longest side = 30 Pythagorean theorem: short leg squared + long leg squared = longest side squared (2x  6)^2 + (2x)^2 = 30^2 (2x  6)(2x  6) + 4x^2 = 900 4x^2  12x  12x + 36 + 4x^2 = 900 8x^2 24x  864 = 0 x^2  3x  108 = 0 (x  12)(x + 9) = 0 x  12 = 0 or x + 9 = 0 x = 12 or x = 9 Since long leg is 2x, 2(9) = 18, and a leg can't have a negative length, discard the negative solution. x = 12 short leg: 2x  6 = 2(12)  6 = 18 long leg: 2x = 2(12) = 24 The lengths are 18 for the short leg, and 24 for the long leg.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Holy crap thank you. Been trying to get a straight answer on this problem for 3 hours. Thank you again.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Oh great word problems ugh hate those :/ will post that next
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
I figured you got all kinds of bs answers except a simple answer to your problem, so it was about time you got one.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
I appreciate it greatly. Some just don't want to hear the word simple these days. To me simple is better and easier for me to understand. It is not I refuse to try I just don't always get it. Thank you again.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
This question is closed sir.
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
To be simple is being fed the answer which I don't believe in. Even if you have Aspergers, Autism, I will never give the answer to somebody.
 one year ago

uselessatmathBest ResponseYou've already chosen the best response.0
Look sir your view is obviously different. I see simple as a way of understanding. Don't like it. Don't respond. Good day.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
I see. You wanted someone to do the work for you, quite contrary to the forum rules. Is there ANY of that reply that you could not have produced? I couldn't get you to write a single symbol past the original post. Why? I'm pretty sure this forum is for learning, not for only answers to be copied and turned in as one's own work. Not a good day.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.