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uselessatmath

  • 2 years ago

Short Leg= 2x-6 Long leg= 2x Longest= 30 Find the missing sides to get 30

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  1. tkhunny
    • 2 years ago
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    Perhaps there was a figure or a description of a figure?

  2. uselessatmath
    • 2 years ago
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    I can't screenshot the figure. The codes in the page prevent it.

  3. tkhunny
    • 2 years ago
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    And you are entirely unable to describe it?

  4. uselessatmath
    • 2 years ago
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    its Pythagoreon Theorem

  5. uselessatmath
    • 2 years ago
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    a squared plus b squared equals c squared

  6. tkhunny
    • 2 years ago
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    Okay, then you should apply that. Can you identify a, b, and c?

  7. uselessatmath
    • 2 years ago
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    I did.

  8. uselessatmath
    • 2 years ago
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    Reread the question.

  9. tkhunny
    • 2 years ago
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    You did what? Fill n the blanks... For the Pythagorean Theorem, I need to identify a, b, and c. a = ?? b = ?? c = 30

  10. uselessatmath
    • 2 years ago
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    I did.

  11. uselessatmath
    • 2 years ago
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    A equals short leg

  12. uselessatmath
    • 2 years ago
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    B equals the other leg

  13. uselessatmath
    • 2 years ago
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    C equals longest leg

  14. tkhunny
    • 2 years ago
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    Okay. What did the Pythagorean Theorem look like when you substituted those values?

  15. uselessatmath
    • 2 years ago
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    When I squared them all?

  16. tkhunny
    • 2 years ago
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    Did you do that? Yes. What did you get?

  17. uselessatmath
    • 2 years ago
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    I have not done it yet because that and the whole problem is where my confusion lies.

  18. tkhunny
    • 2 years ago
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    I think we have established this: a = 2x-6 b = 2x c = 30 We have also established the Pythagorean Theorem \(a^{2} + b^{2} = c^{2}\) Now our task is to substitute the given values into the Pythagorean Theorem. You do that and let's see if you wander off.

  19. uselessatmath
    • 2 years ago
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    I wander off in the beginning.

  20. tkhunny
    • 2 years ago
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    Stop saying that and simply start writing. Change your screen name. Do SOMETHING so that you can win one battle, here. You seem to be in the wrong class. How can we move you toward a more positive outcome? I can't get you to write ANYTHING. That's not good.

  21. uselessatmath
    • 2 years ago
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    I have Aspbergers. Either bear with my incompetence that I was born with or help me find someone who can help.

  22. tkhunny
    • 2 years ago
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    You didn't answer my question. Can you substitute the known values into the known formula, or not? Do you know what substitution means? Have you ever seen the process?

  23. uselessatmath
    • 2 years ago
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    Thank you for your help. Good day.

  24. MarcLeclair
    • 2 years ago
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    What tkhunny is asking is which is the hypothenuse and the adjacent side.

  25. uselessatmath
    • 2 years ago
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    What tk hunny was not understanding is I wrote them already and as neither side is in normal form I am confused.

  26. MarcLeclair
    • 2 years ago
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    Would you be able to use the draw option under the chat log to drwa the picture for us?

  27. uselessatmath
    • 2 years ago
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    maybe im on a laptop

  28. MarcLeclair
    • 2 years ago
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    Just do your best, if you have problem explaining it is much easier to see a picture. If we can't understand your question, we will not be able to help.

  29. uselessatmath
    • 2 years ago
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    |dw:1354487589391:dw|

  30. MarcLeclair
    • 2 years ago
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    okay tell me if im right:|dw:1354487622965:dw|

  31. uselessatmath
    • 2 years ago
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    swap the legs

  32. MarcLeclair
    • 2 years ago
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    the one that are perpendicular?

  33. uselessatmath
    • 2 years ago
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    2x should be on the bottom with 2x minus 6 on the left the 30 is in the right spot

  34. uselessatmath
    • 2 years ago
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    |dw:1354487934867:dw|

  35. MarcLeclair
    • 2 years ago
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    okay that helps, so you want to solve for x. Because you have 1 variable ( which in this case would be x, and I'm assuming you know what variable means) In this case you have a formula relating all angle. We will call it as follow ( because a square + b square = c sqare is too vague and can confuse you): Opposite + adjacent = hypothenuse. Now you're hypothenuse is a mathematical term for what you called " longest leg" which is mathematically wrong to say. Your opposite and adjacent is the two other "Legs" and is relative (therefore meaning it all depends on how you see it) to what you want. I relate the BOTTOM RIGHT angle always. THerefore my opposite side is the 2x-6 and the adjacent is 2x Now come the equation which is as follow: adjacent(squared) + opposite(squared) = hypothenuse (squared) Plug in ( therefore replace the word corresponding to the right side) with the right equation, and solve for x Can you solve for x?

  36. uselessatmath
    • 2 years ago
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    I get legs. I don't get math terms. Can you show me a visual?

  37. MarcLeclair
    • 2 years ago
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    |dw:1354488141269:dw|

  38. uselessatmath
    • 2 years ago
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    o.O

  39. MarcLeclair
    • 2 years ago
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    does this help?

  40. uselessatmath
    • 2 years ago
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    No.

  41. MarcLeclair
    • 2 years ago
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    yikes. Hum alright, ill try another way. When you solve for an equation, at your level, you have only one variable : x

  42. uselessatmath
    • 2 years ago
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    Ok stop just for a moment. You are going way too bloody complex. I don't get complex and I don't get abstract.

  43. MarcLeclair
    • 2 years ago
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    Ah I'm sorry my friend then, I hope you find someone who can give you a better explanation

  44. uselessatmath
    • 2 years ago
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    I have Aspbergers I am used to not being able to find help really.

  45. tkhunny
    • 2 years ago
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    Why as Aspergers a restriction on your ability to visualize, follow abstraction, or communicate symbolically? It that the only diagnosis? You are so SURE that you CAN'T get it, and you know EXACTLY what it is you can't get, that I have to wonder if we don't have other pathologies at play, here. If you don't get abstract, complex, or math symbols, how do you know you have encountered such a thing?

  46. uselessatmath
    • 2 years ago
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    Have you ever looked up Aspbergers? Researched it? Lived it?

  47. uselessatmath
    • 2 years ago
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    By your replies I can say no you have not. Aspbergers is a Social Disorder in the DMV book and can affect the ability to comprehend abstract concepts in Math, English, Reading, Writing, and also affects Social Skills.

  48. tkhunny
    • 2 years ago
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    Yes, Yes, and Yes. But I had no cognitive difficulty related to mathematics. That's why I'm puzzled. It's quite a different presentation than I've previously encountered. I've only seen social aspects.

  49. uselessatmath
    • 2 years ago
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    Not every Aspbergers person is the same.

  50. tkhunny
    • 2 years ago
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    Clearly. Are you aware of what level of abstration can you handle? You seemed to be okay calling a leg of a triangle '2x' and another leg '2x-6'.

  51. uselessatmath
    • 2 years ago
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    It is obvious you can't help me. Good day.

  52. tkhunny
    • 2 years ago
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    Not if you don't talk to me and you just punt.

  53. uselessatmath
    • 2 years ago
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    New problem got it wrong :( let me write the new one

  54. uselessatmath
    • 2 years ago
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    nvm same problem as this one lol

  55. mathstudent55
    • 2 years ago
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    short leg = 2x - 6 long leg = 2x longest side = 30 Pythagorean theorem: short leg squared + long leg squared = longest side squared (2x - 6)^2 + (2x)^2 = 30^2 (2x - 6)(2x - 6) + 4x^2 = 900 4x^2 - 12x - 12x + 36 + 4x^2 = 900 8x^2 -24x - 864 = 0 x^2 - 3x - 108 = 0 (x - 12)(x + 9) = 0 x - 12 = 0 or x + 9 = 0 x = 12 or x = -9 Since long leg is 2x, 2(-9) = -18, and a leg can't have a negative length, discard the negative solution. x = 12 short leg: 2x - 6 = 2(12) - 6 = 18 long leg: 2x = 2(12) = 24 The lengths are 18 for the short leg, and 24 for the long leg.

  56. uselessatmath
    • 2 years ago
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    Holy crap thank you. Been trying to get a straight answer on this problem for 3 hours. Thank you again.

  57. uselessatmath
    • 2 years ago
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    Oh great word problems ugh hate those :/ will post that next

  58. mathstudent55
    • 2 years ago
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    I figured you got all kinds of bs answers except a simple answer to your problem, so it was about time you got one.

  59. uselessatmath
    • 2 years ago
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    I appreciate it greatly. Some just don't want to hear the word simple these days. To me simple is better and easier for me to understand. It is not I refuse to try I just don't always get it. Thank you again.

  60. uselessatmath
    • 2 years ago
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    This question is closed sir.

  61. MarcLeclair
    • 2 years ago
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    To be simple is being fed the answer which I don't believe in. Even if you have Aspergers, Autism, I will never give the answer to somebody.

  62. uselessatmath
    • 2 years ago
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    @MarcLeClair

  63. uselessatmath
    • 2 years ago
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    Look sir your view is obviously different. I see simple as a way of understanding. Don't like it. Don't respond. Good day.

  64. tkhunny
    • 2 years ago
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    I see. You wanted someone to do the work for you, quite contrary to the forum rules. Is there ANY of that reply that you could not have produced? I couldn't get you to write a single symbol past the original post. Why? I'm pretty sure this forum is for learning, not for only answers to be copied and turned in as one's own work. Not a good day.

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