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uselessatmath
 3 years ago
Short Leg= 2x6
Long leg= 2x
Longest= 30
Find the missing sides to get 30
uselessatmath
 3 years ago
Short Leg= 2x6 Long leg= 2x Longest= 30 Find the missing sides to get 30

This Question is Closed

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Perhaps there was a figure or a description of a figure?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I can't screenshot the figure. The codes in the page prevent it.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1And you are entirely unable to describe it?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0its Pythagoreon Theorem

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0a squared plus b squared equals c squared

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Okay, then you should apply that. Can you identify a, b, and c?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Reread the question.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1You did what? Fill n the blanks... For the Pythagorean Theorem, I need to identify a, b, and c. a = ?? b = ?? c = 30

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0A equals short leg

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0B equals the other leg

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0C equals longest leg

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Okay. What did the Pythagorean Theorem look like when you substituted those values?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0When I squared them all?

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Did you do that? Yes. What did you get?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I have not done it yet because that and the whole problem is where my confusion lies.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1I think we have established this: a = 2x6 b = 2x c = 30 We have also established the Pythagorean Theorem \(a^{2} + b^{2} = c^{2}\) Now our task is to substitute the given values into the Pythagorean Theorem. You do that and let's see if you wander off.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I wander off in the beginning.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Stop saying that and simply start writing. Change your screen name. Do SOMETHING so that you can win one battle, here. You seem to be in the wrong class. How can we move you toward a more positive outcome? I can't get you to write ANYTHING. That's not good.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I have Aspbergers. Either bear with my incompetence that I was born with or help me find someone who can help.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1You didn't answer my question. Can you substitute the known values into the known formula, or not? Do you know what substitution means? Have you ever seen the process?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you for your help. Good day.

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0What tkhunny is asking is which is the hypothenuse and the adjacent side.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0What tk hunny was not understanding is I wrote them already and as neither side is in normal form I am confused.

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0Would you be able to use the draw option under the chat log to drwa the picture for us?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0maybe im on a laptop

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0Just do your best, if you have problem explaining it is much easier to see a picture. If we can't understand your question, we will not be able to help.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354487589391:dw

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0okay tell me if im right:dw:1354487622965:dw

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0the one that are perpendicular?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.02x should be on the bottom with 2x minus 6 on the left the 30 is in the right spot

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354487934867:dw

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0okay that helps, so you want to solve for x. Because you have 1 variable ( which in this case would be x, and I'm assuming you know what variable means) In this case you have a formula relating all angle. We will call it as follow ( because a square + b square = c sqare is too vague and can confuse you): Opposite + adjacent = hypothenuse. Now you're hypothenuse is a mathematical term for what you called " longest leg" which is mathematically wrong to say. Your opposite and adjacent is the two other "Legs" and is relative (therefore meaning it all depends on how you see it) to what you want. I relate the BOTTOM RIGHT angle always. THerefore my opposite side is the 2x6 and the adjacent is 2x Now come the equation which is as follow: adjacent(squared) + opposite(squared) = hypothenuse (squared) Plug in ( therefore replace the word corresponding to the right side) with the right equation, and solve for x Can you solve for x?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I get legs. I don't get math terms. Can you show me a visual?

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1354488141269:dw

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0yikes. Hum alright, ill try another way. When you solve for an equation, at your level, you have only one variable : x

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Ok stop just for a moment. You are going way too bloody complex. I don't get complex and I don't get abstract.

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0Ah I'm sorry my friend then, I hope you find someone who can give you a better explanation

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I have Aspbergers I am used to not being able to find help really.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Why as Aspergers a restriction on your ability to visualize, follow abstraction, or communicate symbolically? It that the only diagnosis? You are so SURE that you CAN'T get it, and you know EXACTLY what it is you can't get, that I have to wonder if we don't have other pathologies at play, here. If you don't get abstract, complex, or math symbols, how do you know you have encountered such a thing?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Have you ever looked up Aspbergers? Researched it? Lived it?

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0By your replies I can say no you have not. Aspbergers is a Social Disorder in the DMV book and can affect the ability to comprehend abstract concepts in Math, English, Reading, Writing, and also affects Social Skills.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Yes, Yes, and Yes. But I had no cognitive difficulty related to mathematics. That's why I'm puzzled. It's quite a different presentation than I've previously encountered. I've only seen social aspects.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Not every Aspbergers person is the same.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Clearly. Are you aware of what level of abstration can you handle? You seemed to be okay calling a leg of a triangle '2x' and another leg '2x6'.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0It is obvious you can't help me. Good day.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1Not if you don't talk to me and you just punt.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0New problem got it wrong :( let me write the new one

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0nvm same problem as this one lol

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1short leg = 2x  6 long leg = 2x longest side = 30 Pythagorean theorem: short leg squared + long leg squared = longest side squared (2x  6)^2 + (2x)^2 = 30^2 (2x  6)(2x  6) + 4x^2 = 900 4x^2  12x  12x + 36 + 4x^2 = 900 8x^2 24x  864 = 0 x^2  3x  108 = 0 (x  12)(x + 9) = 0 x  12 = 0 or x + 9 = 0 x = 12 or x = 9 Since long leg is 2x, 2(9) = 18, and a leg can't have a negative length, discard the negative solution. x = 12 short leg: 2x  6 = 2(12)  6 = 18 long leg: 2x = 2(12) = 24 The lengths are 18 for the short leg, and 24 for the long leg.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Holy crap thank you. Been trying to get a straight answer on this problem for 3 hours. Thank you again.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Oh great word problems ugh hate those :/ will post that next

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1I figured you got all kinds of bs answers except a simple answer to your problem, so it was about time you got one.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0I appreciate it greatly. Some just don't want to hear the word simple these days. To me simple is better and easier for me to understand. It is not I refuse to try I just don't always get it. Thank you again.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0This question is closed sir.

MarcLeclair
 3 years ago
Best ResponseYou've already chosen the best response.0To be simple is being fed the answer which I don't believe in. Even if you have Aspergers, Autism, I will never give the answer to somebody.

uselessatmath
 3 years ago
Best ResponseYou've already chosen the best response.0Look sir your view is obviously different. I see simple as a way of understanding. Don't like it. Don't respond. Good day.

tkhunny
 3 years ago
Best ResponseYou've already chosen the best response.1I see. You wanted someone to do the work for you, quite contrary to the forum rules. Is there ANY of that reply that you could not have produced? I couldn't get you to write a single symbol past the original post. Why? I'm pretty sure this forum is for learning, not for only answers to be copied and turned in as one's own work. Not a good day.
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