## Loujoelou Group Title Algebra II question drawing below one year ago one year ago

1. Loujoelou

|dw:1354492999386:dw|

2. Loujoelou

Is this x^(1/12)

3. bay

cross multiply

4. yummydum

${3\over4}x\times{1\over9}x$multiply straight across (3 times 1, 4 times 9, x times x):${3\over36}x^2$simplify:${1\over12}x^2$this can also be written as:$x^2\over12$:) hope this helps :)

5. Loujoelou

|dw:1354493673382:dw| that's what I meant :)

6. Loujoelou

sry if it looked wrong on the 1st drawing :). pretty sure you just multiply the fractions and it becomes x^1/12 right?

7. yummydum

oh im sorry :O okay so you have to add the exponents :) $\huge x^{3\over4}\times x^{1\over9}$so find the common denominator:$\huge x^{27\over36}\times x^{4\over36}$now add:$\huge x^{31\over36}$ when multiplying you add the exponents :)

8. Loujoelou

oh okay thx :) was just reviewing something I hadn't gone over in a long time so was making sure if i was doing it right or not :)

9. yummydum

no problem Lou :)