Loujoelou
Algebra II question below
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Loujoelou
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|dw:1354493963920:dw|
chaguanas
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\[(a ^{m})^{n}=a ^{mn}\]
Loujoelou
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so it'd be x^12/35 right?
yummydum
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when raising an exponent to a power, multiply them:\[\huge\left(x^{4\over5}\right)^{3\over7}\]so do :\[{4\over5}\times{3\over7}\]\[\implies {12\over35}\]so its:\[\huge x^{12\over35}\]
Loujoelou
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thx :)
yummydum
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anytime :)